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Natalija [7]
2 years ago
7

Which information must be known about a compound to find the molecular formula from the empirical formula?

Chemistry
1 answer:
n200080 [17]2 years ago
3 0

The molecular mass of the compound is required to calculate the molecular formula from the empirical formula.

<h3>What is a molecular formula?</h3>

A chemical formula that gives the total number of atoms of each element in each molecule of a substance.

Dividing the molar mass of the compound by the empirical formula mass. The result should be a whole number or very close to a whole number. Multiplying all the subscripts in the empirical formula by the whole number will give the resultant molecular formula.

Hence, the molecular mass of the compound is required to calculate the molecular formula from the empirical formula.

Learn more about the molecular formula here:

brainly.com/question/14425592

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The Molar mass of 50g of water is (18.015 g/mol). Hope this helps
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If an object has a density of 0.55 g/mL, what is its density in cg/L?
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"cg" is centigram, which is one-hundredth of a gram.

I will first convert from g to cg (multiply by 100), then from mL to L (multiply by 1000).

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Question #1: Identify the type of Mutation below
borishaifa [10]

Answer:

Deletion

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In the particular case of this question, the original is TTCGATA while the copy is TTGATA. If you look closely at the two, you will notice that the C has been omitted. This is an example of  deletion.

5 0
2 years ago
- Explain how ionic bonds, covalent bonds, and metallic bonds each form and how.
-Dominant- [34]

Answer:  -Ionic bonds form when one atom provides electrons to another atom. Covalent Bonds: Covalent bonds form when two atom shares their valence electrons. Metallic Bonds: Metallic bonds form when a variable number of atoms share a variable number of electrons in a metal lattice.

-Covalent Bonds.

Covalent Compounds. Contain no metals and no ions. Covalent compounds contain nonmetals only.

Example:

Ionic Compounds. A metal with a non-metal. Doesn't use prefixes for naming. Name the metal and change the nonmetal ending to -ide.

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6 0
2 years ago
How much 6.0 m hno3 is needed to neutralize 39ml of 2 m koh
Sever21 [200]

Answer:

13mL

Explanation:

Step 1:

The balanced equation for the reaction. This is given below:

HNO3 + KOH —> KNO3 + H2O

From the balanced equation above, we obtained the following data:

Mole ratio of the acid (nA) = 1

Mole ratio of the base (nB) = 1

Step 2:

Data obtained from the question.

This includes the following:

Molarity of the acid (Ma) = 6M

Volume of the acid (Va) =?

Volume of the base (Vb) = 39mL

Molarity of the base (Mb) = 2M

Step 3:

Determination of the volume of the acid.

Using the equation:

MaVa/MbVb = nA/nB, the volume of the acid can be obtained as follow:

MaVa/MbVb = nA/nB

6 x Va / 2 x 39 = 1/1

Cross multiply to express in linear form

6 x Va = 2 x 39

Divide both side by 6

Va = (2 x 39)/6

Va = 13mL

Therefore, the volume of the acid (HNO3) needed for the reaction is 13mL

5 0
3 years ago
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