0.433 is already rounded to the hundredths so to round it to the nearest tenths, remove the last number.
Your answer is 0.43
4x - 5(x - 2) = 12x + 4 - x
4x - 5(x) - 5(-2) = 12 - x + 4
4x - 5x + 10 = 11x + 4
-x + 10 = 11x + 4
<u>+ x + x </u>
10 = 12x + 4
<u>- 4 - 4</u>
<u>6</u> = <u>12x</u>
12 12
0.5 = x
Answer:
5% each hour
Step-by-step explanation:
in 1.5 hours she loses 7.5% of battery
get the percentage of loss for a half hour.
divide 1.5 and 7.5 by 3.
That gives a loss of 2.5% for every half hour.
Which gives a loss of 5% percent an hour.
<u>Answer:</u>
![\boxed{\pink{\sf The \ number \ of \ cubes \ that \ can \ be \ fitted \ is 60 .}}](https://tex.z-dn.net/?f=%5Cboxed%7B%5Cpink%7B%5Csf%20The%20%5C%20number%20%5C%20of%20%5C%20cubes%20%5C%20that%20%5C%20can%20%5C%20be%20%5C%20fitted%20%5C%20is%2060%20.%7D%7D)
<u>Step-by-step explanation:</u>
Given dimensions of the box = 20cm × 6cm × 4cm .
Dimension of the cube = 2cm × 2cm × 2cm .
Therefore the number of cubes that can be fitted into the box will be equal to the Volume of box divided by the Volume of the cube. So ,
![\boxed{\red{\bf \implies No. \ of \ cubes \ = \dfrac{Volume \ of \ box}{Volume \ of \ cube }}}](https://tex.z-dn.net/?f=%5Cboxed%7B%5Cred%7B%5Cbf%20%5Cimplies%20No.%20%5C%20of%20%5C%20cubes%20%5C%20%3D%20%5Cdfrac%7BVolume%20%5C%20of%20%5C%20box%7D%7BVolume%20%5C%20of%20%5C%20cube%20%7D%7D%7D)
![\bf \implies n_{cubes} = \dfrac{20cm \times 6cm \times 4cm .}{2cm \times 2cm \times 2cm } \\\\\bf\implies n_{cubes} = 10 \ times 3cm \times 2cm \\\\\implies \boxed{\bf n_{cubes}= 60 }](https://tex.z-dn.net/?f=%5Cbf%20%5Cimplies%20n_%7Bcubes%7D%20%3D%20%5Cdfrac%7B20cm%20%5Ctimes%20%206cm%20%5Ctimes%204cm%20.%7D%7B2cm%20%20%5Ctimes%202cm%20%20%5Ctimes%202cm%20%7D%20%5C%5C%5C%5C%5Cbf%5Cimplies%20n_%7Bcubes%7D%20%20%3D%2010%20%5C%20times%203cm%20%5Ctimes%202cm%20%5C%5C%5C%5C%5Cimplies%20%5Cboxed%7B%5Cbf%20n_%7Bcubes%7D%3D%2060%20%7D)
<h3>
<u>Hence</u><u> the</u><u> </u><u>number</u><u> </u><u>of</u><u> </u><u>cubes</u><u> </u><u>that</u><u> </u><u>can</u><u> </u><u>be</u><u> </u><u>fitted</u><u> </u><u>in</u><u> the</u><u> </u><u>box </u><u>is</u><u> </u><u>6</u><u>0</u><u> </u><u>.</u></h3>
2n+2(n-4)=56
2n+2n-8=56
4n-8=56
4n=64
n=16
1st side is 16
2nd side is 12