Answer:
they are equal.
Explanation:
1 mol = 6.022 × 10^23 (Avogadro's constant), which is the number of atoms in 1 mol of any element. Doesn't matter what their atomic mass is, although, of course, 1 mol of carbon weighs less than 1 mol of calcium, but its because their mass is different, but the point is, in 1 mol of any element there is 6.03*10^23 atoms
This is like saying, what weighs more, 10 kg of feathers or 10 kg of metal
Answer: The correct answer is A. 11.5 atm. The temperature is held constant at 293 K, therefore, we can use Boyle's Law to determine the initial pressure. Boyle's Law states that there is an inverse relationship between pressure and volume of gases. Therefore, as volume increases, the pressure will decrease and vice versa.
Further Explanation:
Boyle's Law can be mathematically expressed as:

In this problem, we are given the values:
P(initial) = ?
V(initial) = 80 L
P (final) = 0.46 atm
V (final) = 2000 L
Plugging in these values into the equation:

The initial pressure was 11.5 atm. Since the volume increased or expanded, the space where the gas particles move is bigger, so the frequency of collisions with the wall of the container and with other particles are effectively decreased. This, therefore, decreases the pressure from 11.5 to 0.46 atm.
Learn More
- Learn about Charles' Law brainly.com/question/1421697
- Learn about Ideal Gas Law brainly.com/question/6534668
- Learn about Gay - Lusaac's Law brainly.com/question/1358307
Keywords: gas, Boyle's Law, Ideal Gas Law
The electrons closer to the nucleus would have more energy than the electrons farther away from the nucleus.
<u>Answer:</u> The temperature of the system will be 1622 K
<u>Explanation:</u>
The equation relating the pre-exponential factor and activation energy follows:

where,
D = diffusion coefficient = 
= pre-exponential constant = 
= activation energy of iron in cobalt = 273,300 J/mol
R = Gas constant = 8.314 J/mol.K
T = temperature = ?
Putting values in above equation, we get:

Hence, the temperature of the system will be 1622 K