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Ne4ueva [31]
3 years ago
6

The combustion of ammonia in the presence of excess oxygen yields no2 and h2o: 4 nh3 (g) + 7 o2 (g) â 4 no2 (g) + 6 h2o (g) the

combustion of 28.8 g of ammonia consumes ________ g of oxygen.
Chemistry
1 answer:
VLD [36.1K]3 years ago
8 0
The answer would be 118.68 g.
Explanation for this is:4 moles of NH3 give 4 moles of NO2 
so 1mole of NH3 will give 1 mole of NO2 
43.9 grams of NH3 contains 2.58 moles 
so 2.58 moles will be produced of NO2 
which is 118.7 grams this the amount of oxygen that is used.
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The awnser is A. Idek I looked it up so yeah that’s the awnser
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3 years ago
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Suppose you have just added 200.0 ml of a solution containing 0.5000 moles of acetic acid per liter to 100.0 ml of 0.5000 M NaOH
uranmaximum [27]

Answer:

The final pH is 3.80

Explanation:

Step 1: Data given

Volume of acetic acid = 200.0 mL = 0.200 L

Number of moles acetic acid = 0.5000 moles

Volume of NaOH = 100.0 mL = 0.100 L

Molarity of NaOH = 0.500 M

Ka of acetic acid = 1.770 * 10^-5

Step 2: The balanced equation

CH3COOH + NaOH → CH3COONa + H2O

Step 3: Calculate moles

moles = molarity * volume

Moles NaOH = 0.500 M * 0.100 L

Moles NaOH = 0.0500 moles

Step 4: Calculate the limiting reactant

For 1 mol CH3COOH we need 1 mol NaOH to produce 1 mol CH3COONa and 2 moles H2O

NaOH is the limiting reactant. It will completely be consumed (0.0500 moles). CH3COOH is in excess. There will react 0.0500 moles . There will remain 0.500 - 0.0500 = 0.450 moles

There will be produced 0.0500 moles CH3COONa

Step 5: Calculate the total volume

Total volume = 200.0 mL + 100.0 mL = 300.0 mL

Total volume = 0.300 L

Step 6: Calculate molarity

Molarity = moles / volume

[CH3COOH] = 0.450 moles / 0.300 L

[CH3COOH] = 1.5 M

[CH3COONa] = 0.0500 moles / 0.300 L

[CH3COONa]= 0.167 M

Step 7: Calculate pH

pH = pKa + log[A-]/ [HA]

pH = -log(1.77*10^-5) + log (0.167/ 1.5)

pH = 4.75 + log (0.167/1.5)

pH = 3.80

The final pH is 3.80

7 0
3 years ago
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6 0
3 years ago
An inexpensive and accurate method of measuring the quantity of electricity flowing through a circuit is to pass the current thr
Paha777 [63]

Total of 127.013 C of charge is passed

Given

 weight of Ag solution before current has passed = 1.7854 g

  weight of Ag solution after current has passed = 1.8016 g

  Molecular mass of Ag = 107.86 g

  Faraday's Constant = 96485

First of all we have to apply Faraday's First Law of Electrolysis i.e

         m = ZQ

  where

Z is propotionality constant (g/C)

Q is charge (C)

Hence,

 Z = Atomic mass of substance/ Faraday's Constant

    = \frac{107.86 g}{96485 C}

    = 0.0011178 g/C

Now ,

   change in mass before and after the passing of current (Δm)

       Δm = 1.8016g-1.7854g

             =   0.0162g

    Now  amount of coulombs passed = \frac{0.142g}{0.0011178 g/C }

          amount of coulombs passed = 127.03524 C

Thus from the above conclusion we can say that amount of coulombs have passed is 127.03524 C

Learn more about Electrolysis here: brainly.com/question/16929894

#SPJ4

7 0
2 years ago
Please help me quickly!!!
Eduardwww [97]
It is an endothermic reaction, as the product have more energy than the reactants. So, the answer would be A. Brainliest? Hope this helped!❤️
4 0
3 years ago
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