The last one. A mixture isn’t chemically combined.
Answer:
1.1grams
Explanation:
Find moles of water:
4.5x10^22/(6.02x10^23)=0.07mol
Find molar mass of the water
O=16.00g/mol
0.07x 16.00=1.1 grams
Answer:
(a). 132 × 10^-9 s = 132 nanoseconds.
(b)..176.5 pico-seconds.
Explanation:
(a). At one torr, the first thing to do is to find the speed and that can be done by using the formula below;
Speed = [ (8 × R × T)/ Mm × π]^1/2.
Where Mm = molar mass, T = temperature and R = gas constant.
Speed= [ ( 8 × 8.314 × 300)/ 131.293 × π × 10^-3)^1/2. = 220m/s.
The next thing to do now is to calculate for the degree of collision which can be calculated by using the formula below;
Degree of collision = √2 × π × speed × d^2 × pressure/ K × T.
Note that pressure = 1 torr = 133.32 N/m^2 and d = collision diameter.
Degree of collision = √2 × π × 220 × (4.9 × 10^-10)^2 × 133.32/ 1.38 × 10^-23 × 300.
Degree of collision = 7.55 × 10^6 s^-1.
Thus, 1/ 7.55 × 10^6. = 132 × 10^-9 s = 132 nanoseconds.
(b). At one bar;
1/10^5 × 10^3 × 56.65 = 1.765 × 10^-10 = 176.5 pico-seconds.
Answer: Temperature in constant pressure is 286 K
Explanation: If pressure remains constant, then V/T = constant.
V1 = 350 ml and T1 = 200 K and V2 = 500 ml. V1/T1 = V2/T2
and T2 = T1· V2 / V1 = 200 K · 500 ml / 300 ml = 285,7 K
<span>1 meter = 100 cm
so 1cm is 1/100 *100 = 1% error.
1 kilogram = 1000g
so 1g is 1/1000 * 100 = 0.1% error.
as 1%>0.1%, the 1cm in a meter is the greater error</span><span>
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