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WINSTONCH [101]
3 years ago
11

5 and 3/8 + 2 and 2/8

Mathematics
2 answers:
zmey [24]3 years ago
4 0
7and 5/8
5+2 is 7
3/8+2/8 is 5/8
7+5/8 is
7 and 5/8
cestrela7 [59]3 years ago
4 0
5 and 3/8 + 2 and 2/8 = 7.625
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Simplify the following expression by combining like terms:<br> - 2 +63 +2 - 2x + 8 - 4:
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Answer:

6+4x-3z

Step-by-step explanation:

<u>-2</u>+6x+z-2x<u>+8</u>-4z

6<u>+6x</u>+z<u>-2x</u>-4z

6+4x<u>+z-4z</u>

6+4x-3z

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Please help. URGENT. THANK YOU
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Please help me with this 3x=9
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3 years ago
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(K3+2k2-82k-28)/(k+10)
Ne4ueva [31]

So for this, we will be using synthetic division. To set it up, have the equation so that the divisor is -10 (since that is the solution of k + 10 = 0) and the dividend are the coefficients. Our equation will look as such:

<em>(Note that synthetic division can only be used when the divisor is a 1st degree binomial)</em>

  • -10 | 1 + 2 - 82 - 28
  • ---------------------------

Now firstly, drop the 1:

  • -10 | 1 + 2 - 82 - 28
  •       ↓
  • -------------------------
  •        1

Next, you are going to multiply -10 and 1, and then combine the product with 2.

  • -10 | 1 + 2 - 82 - 28
  •       ↓ - 10
  • -------------------------
  •        1 - 8

Next, multiply -10 and -8, then combine the product with -82:

  • -10 | 1 + 2 - 82 - 28
  •       ↓ -10 + 80
  • -------------------------
  •        1 - 8 - 2

Next, multiply -10 and -2, then combine the product with -28:

  • -10 | 1 + 2 - 82 - 28
  •       ↓ -10 + 80 + 20
  • -------------------------
  •        1 - 8 - 2 - 8

Now, since we know that the degree of the dividend is 3, this means that the degree of the quotient is 2. Using this, the first 3 terms are k^2, k, and the constant, or in this case k² - 8k - 2. Now what about the last coefficient -8? Well this is our remainder, and will be written as -8/(k + 10).

<u>Putting it together, the quotient is k^2-8k-2-\frac{8}{k+10}</u>

8 0
3 years ago
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