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2 years ago

7

What is the perimeter of A’B’C’D’?

1 answer:

Sophie [7]2 years ago

5 0

$\displaystyle\bf\\\textbf{At any translation of a quadrilateral the sides remain the same,}\\\\\textbf{the angles remain the same.}\\\\\textbf{It turns out that the quadrilateral remains the same.}\\\\P_{A'B'C'D'}=P_{ABCD}=AB+BC+CD+DA=\\\\~~~~~~~~~~~~~~=2.2+4.5+6.1+1.4=\boxed{\bf14.2}$

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blagie [28]

Answer:

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Step-by-step explanation:

we know that

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step 1

Find the area of the circle

the area of the circle is equal to

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we have

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substitute

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step 2

Find the area of the sector

we know that

The area of the circle subtends a central angle of 360 degrees

so

by proportion find out the area of a sector by a central angle of 72 degrees

$\frac{25\pi}{360}=\frac{x}{72}\\ \\x=72*25\pi /360\\ \\x=5\pi\ ft^{2}$

step 3

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The area of the triangle is equal to

$A=\frac{1}{2}(2.9+2.9)(4)= 11.6\ ft^{2}$

step 4

Find the area of the shaded region

Subtract the area of the triangle from the area of the sector

$(5\pi-11.6)\ ft^{2}$

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Answer:

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