All categories

3 years ago

What is the perimeter of A’B’C’D’?

Mathematics

1 answer:

Sophie [7]3 years ago

5 0

$\displaystyle\bf\\\textbf{At any translation of a quadrilateral the sides remain the same,}\\\\\textbf{the angles remain the same.}\\\\\textbf{It turns out that the quadrilateral remains the same.}\\\\P_{A'B'C'D'}=P_{ABCD}=AB+BC+CD+DA=\\\\~~~~~~~~~~~~~~=2.2+4.5+6.1+1.4=\boxed{\bf14.2}$

You might be interested in

What can you say about the end behavior of the function f(x)=-4x^6+6x^2-52

shepuryov [24]

Answer:

As x gets smaller, pointing to negative infinity, the value of f decreses, pointing to negative infinity.

As x gets increases, pointing to positve infinity, the value of f decreses, pointing to negative infinity.

Step-by-step explanation:

To find the end behaviour of a function f(x), we calculate these following limits:

$\lim_{x \to +\infty} f(x)$

And

$\lim_{x \to -\infty} f(x)$

In this question:

$f(x) = -4x^{6} + 6x^{2} - 52$

At negative infinity:

$\lim_{x \to -\infty} f(x) = \lim_{x \to -\infty} -4x^{6} + 6x^{2} - 52$

When the variable points to infinity, we only consider the term with the highest exponent. So

$\lim_{x \to -\infty} -4x^{6} + 6x^{2} - 52 = \lim_{x \to -\infty} -4x^{6} = -4*(-\infty)^{6} = -(\infty) = -\infty$

So as x gets smaller, pointing to negative infinity, the value of f decreses, pointing to negative infinity.

Positive infinity:

$\lim_{x \to \infty} f(x) = \lim_{x \to \infty} -4x^{6} + 6x^{2} - 52 = \lim_{x \to \infty} -4x^{6} = -4*(\infty)^{6} = -(\infty) = -\infty$

So as x gets increases, pointing to positve infinity, the value of f decreses, pointing to negative infinity.

8 0

3 years ago

Two cell phone companies have different rate plans. Runfast has monthly charges $10 plus $4 per gig of data. B A &D’s monthl

melomori [17]

BA&D's plan is better for those who use less data. The intersection point of the two plans is (2, 18), which means that both plans cost $18 when you use 2G of data. Anything using more data than that is less expensive with BA&D's plan.

To find the intersection point,
6+6g=10+4g

We cannot have a variable on both sides, so we will subtract 4g from both sides:
6+6g-4g=10+4g-4g
6+2g=10

Subtract 6 from both sides:
6+2g-6=10-6
2g=4

Divide both sides by 2:
2g/2 = 4/2
g = 2

This is the point where the plans cost the same. If we try a number smaller than 2 in both plans,
6+6(1) = 6+6 = 12
10+4(1) = 10+4 = 14

BA&D's plan is less.

6 0

3 years ago

70.5 - 6.81 =<br> 63.69<br> 63.71<br> 64.69<br> 77.31

djverab [1.8K]

Answer:

63.69

Step-by-step explanation:

8 0

3 years ago

If M (6,8) is the midpoint of line segment AB, and if A has coordinates (2,3) , find the coordinates of B.

sveticcg [70]

Graphing is one way to do the problem.But sometimes, graphing it is hard to do.So here’s an algebraic method.
If M(m1, m2) is the midpoint of two points A(x1, y1) and B(x2, y2),then m1 = (x1 + x2)/2 and m2 = (y1 + y2)/2.In other words, the x-coordinate of the midpointis the average of the x-coordinates of the two points,and the y-coordinate of the midpointis the average of the y-coordinates of the two points.
Let B have coordinates (x2, y2) in our problem.Then we have that 6 = (2 + x2)/2 and 8 = (3 + y2)/2.
Solving for the coordinates gives x2 = 10, y2 = 13

8 0

3 years ago

There are some goats, cows and, sheep. 2/5 of the animals were goats. There were three times as many sheep than cows. If there w

kobusy [5.1K]

Answer:

81 sheep were there on the farm

Step-by-step explanation:

Consider the provided information.

Let x represents the number of goats.

y represents the number of cows.

z represents the number of sheep.

Therefore, the total number of animals are x+y+z