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3 years ago

15

A runner jogs 1 km south to a school, then jogs 1km west to a restaurant. What is the position of the runner relative to the sch

ool

1 answer:

Finger [1]3 years ago

7 0

Answer:

12

Explanation:

yeah

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How can I feel pain when I hit a table with my bare hands (Physics)

Sidana [21]

When your hand hits the table the table will vibrate and your hand will be numb for two to three seconds

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3 years ago

A 95.0 kg satellite moves on a circular orbit around the Earth at the altitude h=1.20*103 km. Find: a) the gravitational force e

Natali5045456 [20]

Answer:

a) $F = 660.576\,N$ , b) $a_{c} = 6.953\,\frac{m}{s^{2}}$ , c) $v \approx 7255.423\,\frac{m}{s}$ , $\omega = 9.583\times 10^{-4}\,\frac{rad}{s}$ , d) $T \approx 1.821\,h$

Explanation:

a) The gravitational force exerted by the Earth on the satellite is:

$F = G\cdot \frac{m\cdot M}{r^{2}}$

$F = \left(6.674\times 10^{-11}\,\frac{m^{3}}{kg\cdot s^{2}} \right)\cdot \frac{(95\,kg)\cdot (5.972\times 10^{24}\,kg)}{(7.571\times 10^{6}\,m)^{2}}$

$F = 660.576\,N$

b) The centripetal acceleration of the satellite is:

$a_{c} = \frac{660.576\,N}{95\,kg}$

$a_{c} = 6.953\,\frac{m}{s^{2}}$

c) The speed of the satellite is:

$v = \sqrt{a_{c}\cdot R}$

$v = \sqrt{\left(6.953\,\frac{m}{s^{2}} \right)\cdot (7.571\times 10^{6}\,m)}$

$v \approx 7255.423\,\frac{m}{s}$

Likewise, the angular speed is:

$\omega = \frac{7255.423\,\frac{m}{s} }{7.571\times 10^{6}\,m}$

$\omega = 9.583\times 10^{-4}\,\frac{rad}{s}$

d) The period of the satellite's rotation around the Earth is:

$T = \frac{2\pi}{\left(9.583\times 10^{-4}\,\frac{rad}{s} \right)} \cdot \left(\frac{1\,hour}{3600\,s} \right)$

$T \approx 1.821\,h$

6 0

2 years ago

A dramatic demonstration, called "singing rods," involves a long, slender aluminum rod held in the hand near the rod's midpoint.

Korvikt [17]

More vibration = higher frequency

8 0

3 years ago

a wagon weighing 1800 newtons is pulled by a horse at a speed of 0.40 m/sec. what is the power of this horse?

adelina 88 [10]

Power is equal to (Newtons x meters)/time, also known as the following equation...

P = Fd/t

Your force is 1800Newtons and your velocity is 0.4m/s
Velocity is equal to distance/time, also known as the following equation...

v = d/t

So your equation is basically P = Fv

P = 1800N x 0.4m/s

P = 720 Watts

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3 years ago

An electromagnetic wave can be described as a transverse magnetic wave moving

neonofarm [45]

Answer:

(B) perpendicular to and in the same direction as the transverse electric wave

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2 years ago