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otez555 [7]
2 years ago
15

CAN SOMEONE TELL ME THE answer for this ?

Physics
2 answers:
Anna007 [38]2 years ago
5 0

Answer:

C. Light from the sun is reflected by the moon's surface

Explanation:

In some parts the Light reaches, it gets lighted up and the parts where light does not reaches we can't see so we see the phrases of the moon .

Paladinen [302]2 years ago
4 0

Answer:

b. light from earth is reflected by the moon surface

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lara31 [8.8K]

Explanation:

water contains dissolved salts which can create ions

7 0
3 years ago
Read 2 more answers
Scientific work is currently underway to determine whether weak oscillating magnetic fields can affect human health. For example
nlexa [21]

Answer:

The maximum emf that can be generated around the perimeter of a cell in this field is 1.5732*10^{-11}V

Explanation:

To solve this problem it is necessary to apply the concepts on maximum electromotive force.

For definition we know that

\epsilon_{max} = NBA\omega

Where,

N= Number of turns of the coil

B = Magnetic field

\omega = Angular velocity

A = Cross-sectional Area

Angular velocity according kinematics equations is:

\omega = 2\pi f

\omega = 2\pi*61.5

\omega =123\pi rad/s

Replacing at the equation our values given we have that

\epsilon_{max} = NBA\omega

\epsilon_{max} = NB(\pi (\frac{d}{2})^2)\omega

\epsilon_{max} = (1)(1*10^{-3})(\pi (\frac{7.2*10^{-6}}{2})^2)(123\pi)

\epsilon_{max} = 1.5732*10^{-11}V

Therefore the maximum emf that can be generated around the perimeter of a cell in this field is 1.5732*10^{-11}V

6 0
3 years ago
1. Which of the following best describes a nebula?
Gekata [30.6K]

Answer:

D

Explanation:

denser clouds of particles found in the interstellar medium

8 0
2 years ago
The New Horizons probe flew past Pluto in July 2015. At the time, Pluto was about 32 AU from Earth. How long did it take for com
UkoKoshka [18]

Answer:

15944.6 sec

Explanation:

d = distance of Pluto from earth = 32 AU = 32 x 1.496 x 10¹¹ m

v = speed of light = 1.08 x 10⁹ km/hr = ( 1.08 x 10⁹) (0.278) m/s

t = time taken for the communication to reach from probe to earth = ?

Using the equation

d = v t

Inserting the values given

32 x 1.496 x 10¹¹ = (( 1.08 x 10⁹) (0.278)) t

t = 15944.6 sec

t = 1.6 x 10⁴ sec

4 0
2 years ago
A solid spherical conductor has a radius of 12 cm. The electric field at 24 from the center of the sphere has a magnitude of 640
hoa [83]

Answer:

Charge density on the sphere = 2.2 × 10⁻⁸ C/m²

Explanation:

Given:

Radius of sphere (r) = 12 cm = 0.12 m

Distance from the electric field R = 24 cm = 0.24 m

Magnitude (E) = 640 N/C

Find:

Charge density on the sphere

Computation:

Charge on the sphere (q) = (1/K)ER²            (K = 9 × 10⁹)

Charge on the sphere (q) = [1/(9 × 10⁹)](640)(0.24)²

Charge on the sphere (q) = 4 × 10⁻⁹ C

Charge density on the sphere = q / [4πr²]

Charge density on the sphere = [4 × 10⁻⁹] / [4(3.14)(0.12)²]

Charge density on the sphere = [4 × 10⁻⁹] / [0.18]

Charge density on the sphere = 2.2 × 10⁻⁸ C/m²

4 0
2 years ago
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