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Romashka [77]
3 years ago
10

Simple Question! Help!

Physics
2 answers:
Korvikt [17]3 years ago
8 0

<em>60km</em><em>/</em><em>hr</em><em>.</em><em>.</em>

<em>I</em><em> </em><em>think</em><em> </em><em>so</em><em>.</em><em>.</em><em>.</em><em>.</em>

Butoxors [25]3 years ago
3 0
<h3>Answer:</h3>

60 km/s

<h3>step-step wise explaination:</h3>

60 kilometers / 60 minutes

= 1 kilometer / minute

as we know to convert kilometer / min we should multiply 60 to speed value

therefore, (1×60/ 1) km/hr=60 km/ hr

if you want to know why 60 multiplied with it then read this

1 km/min to km/hr

1 minute = 1/60 hour

so, for converting minute to hour we multiply 1/60

when it goes to top then it multiplied

I know it's little complicated let see it by equation

1 km/min = (1 / 1×1/60) km/h

=(1 / 1/60) km/hr

= 60 km/hr

( note there is no change in km so it remains without multiplied)

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4 years ago
A solid sphere of radius 40.0 cm has a total positive charge of 16.2 μC uniformly distributed throughout its volume. Calculate t
Jobisdone [24]

Answer:

(a) E=0  :   0 cm from the center of the sphere

(b) E= 227.8*10³ N/C   :    10.0 cm from the center of the sphere

(c)E= 911.25*10³ N/C    :    40.0 cm from the center of the sphere

(d)E= 411.84 * 10³ N/C  :    59.5 cm from the center of the sphere

Explanation:

If we have a uniform charge sphere we can use the following formulas to calculate the Electric field due to the charge of the sphere

E=\frac{K*Q}{r^{2} } : Formula (1) To calculate the electric field in the region outside the sphere r ≥ a

E=k*\frac{Q}{a^{3} } *r :Formula (2) To calculate the electric field in the inner region of the sphere. r ≤ a

Where:

K: coulomb constant

a: sphere radius

Q:  Total sphere charge

r : Distance from the center of the sphere to the region where the electric field is calculated

Equivalences

1μC=10⁻⁶C

1cm= 10⁻²m

Data

k= 9*10⁹ N*m²/C²

Q=16.2 μC=16.2 *10⁻⁶C

a= 40 cm = 40*10⁻²m = 0.4m

Problem development

(a)Magnitude of the electric field at  0 cm :

We replace r=0 in the formula (2) , then, E=0

(b) Magnitude of the electric field at 10.0 cm from the center of the sphere

r<a , We apply the Formula (2):

E=9*10^{9} *\frac{16.2*10^{-6} }{0.4^{3} } *0.1

E= 227.8*10³ N/C

(c) Magnitude of the electric field at 40.0 cm from the center of the sphere

r=a, We apply the Formula (1) :

E=\frac{9*10^{9}*16.2*10^{-6} }{0.4^{2} }

E= 911.25*10³ N/C

(d) Magnitude of the electric field at 59.5 cm from the center of the sphere  

r>a , We apply the Formula (1) :

E=\frac{9*10^{9}*16.2*10^{-6} }{0.595^{2} }

E= 411.84 * 10³ N/C

4 0
3 years ago
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