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Romashka [77]
3 years ago
10

Simple Question! Help!

Physics
2 answers:
Korvikt [17]3 years ago
8 0

<em>60km</em><em>/</em><em>hr</em><em>.</em><em>.</em>

<em>I</em><em> </em><em>think</em><em> </em><em>so</em><em>.</em><em>.</em><em>.</em><em>.</em>

Butoxors [25]3 years ago
3 0
<h3>Answer:</h3>

60 km/s

<h3>step-step wise explaination:</h3>

60 kilometers / 60 minutes

= 1 kilometer / minute

as we know to convert kilometer / min we should multiply 60 to speed value

therefore, (1×60/ 1) km/hr=60 km/ hr

if you want to know why 60 multiplied with it then read this

1 km/min to km/hr

1 minute = 1/60 hour

so, for converting minute to hour we multiply 1/60

when it goes to top then it multiplied

I know it's little complicated let see it by equation

1 km/min = (1 / 1×1/60) km/h

=(1 / 1/60) km/hr

= 60 km/hr

( note there is no change in km so it remains without multiplied)

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Two 2.00 cm * 2.00 cm plates that form a parallel-plate capacitor are charged to { 0.708 nC. What are the electric field strengt
lisov135 [29]

Answer:

(a) E=200000Volts/meter

(b) E=200000Volts/meter

Explanation:

Given data

Area A=4.0 cm²=0.0004 m²

Electric permittivity ε=8.854×10⁻¹² farads/meter

Charge q=0.708 nC

To find

(a) Potential at distance=1.00mm

(b) Potential at distance=2.00mm

Solution

For (a) Potential at distance=1.00mm

First we need to find the capacitance

So

C=E*A/D\\C=8.854*10^{-12}*(0.0004/1.00*10^{-3} )\\ C=3.5416*10^{-12}farads

As we know that

Q=CV\\V=Q/C\\V=(0.708*10^{-9}C )/3.5416*10^{-12}farads\\V=200Volts

So Electric potential is given as:

E=V/d\\E=(200V)/(1*10^{-3}m )\\E=200000Volts/meter

For (b) Potential at distance=2.00mm

First we need to find the capacitance

So

C=E*A/D\\C=8.854*10^{-12}*(0.0004/2.00*10^{-3} )\\ C=1.7708*10^{-12}farads

As we know that

Q=CV\\V=Q/C\\V=(0.708*10^{-9}C )/1.7708*10^{-12}farads\\V=400Volts

So Electric potential is given as:

E=V/d\\E=(400V)/(2.0*10^{-3}m )\\E=200000Volts/meter

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