Answer:
A) F = 1.09 10 5 N, b) Yes
Explanation:
Part A
For this exercise we need the number of free electrons in copper, as the valence of copper +1 there is a free electron for each atom. Let's use the concept of density to find the mass of copper in the sphere
ρ = m / V
.m = ρ V = ρ 4/3 π r³
The radius is half the diameter
r = 1.9 10⁻² / 2 = 0.95 10⁻² m
ρ = 8960 kg / m3
m = 8960 4/3 π (0.95 10⁻²)³
m = 3.2179 10⁻² kg
The molecular weight of copper is 63,546 g / mol which has 6,022 10²³ atoms
With this we can use a rule of proportions to enter the number of atom is this mass
#_atom = 6.022 10²³ 3.2179 10⁻² / 63.546 10⁻³
#_atom = 3,049 10²³
Therefore there is the same number of electrons, as they indicate that the charge of the protone and the electon differs by 1/10⁹ the total charge for each spherical is
q = e / 10⁹ #_atom
q = e / 10⁹ 3,049 1023
q = 3,049 10⁴ (-1.6 10⁻¹⁹)
q = -4,878 10-5 C
Electric force is
F = k q₁q₂ / r²
F = k q² / r²
Let's calculate
F = 8.99 10⁹ (4.878 10⁻⁵)²2 / (1.4 10⁻²)²
F = 1.09 10 5 N
This is a force of repulsion.
Part B
The magnitude of this force is in very easy to detect
