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Studentka2010 [4]

3 years ago

10

Which body have a period of revolution of 29.6 days?

2 answers:

Kaylis [27]3 years ago

6 0

It would be C the moon because the total of all positions (new moon, first quarter, third quarter, full moon, waxing crescent, waning crescent, waxing gibbous, waning gibbous) of the moon would take about 29.6 days on a regular calendar. I hope this helps. :)

adelina 88 [10]3 years ago

4 0

The moon is the closest one on the list. Its period of revolution around the Earth is 27.32 days. (But the length of the cycle of phases, like from one Full Moon to the next one, is 29.53 days.)

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jekas [21]

C.) cool feet walking across a hot pavement.

The reason because the other ones deals with radiation. Only C.) is the right answer because the feet is touching the hot pavement which is conduction.

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3 years ago

__________ is when all light rays bounce off an object at the same angle.

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2 years ago

The acceleration of gravity is -9.8 m/s2. A sling shot fires a rock straight up into the air with a speed of +39.2 m/s. 1. what

Vanyuwa [196]

Given that,

The acceleration of gravity is -9.8 m/s²

Initial velocity, u = 39.2 m/s

Time, t = 2 s

To find,

The final velocity of the shot.

Solution,

Let v is the final velocity of sling shot. Using first equation of motion to find it.

v = u +at

Here, a = -g

v = u-gt

v = (39.2)-(9.8)(2)

v = 19.6 m/s

So, its velocity after 2 seconds is 19.6 m/s.

4 0

2 years ago

In figures (a)-(d), a block moves to the right in the positive x direction through the displacement Δx while under the influence

Elena L [17]

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2 years ago

A small bolt with a mass of 41.0 g sits on top of a piston. The piston is undergoing simple harmonic motion in the vertical dire

EleoNora [17]

Answer:

Amplitude will be equal to 0.091 m

Explanation:

Given mass of the slits = 41 gram = 0.041 kg

Frequency f = 1.65 Hz

So angular frequency $\omega =2\pi f=2\times 3.14\times 1.65=10.362rad/sec$

Angular frequency is equal to $\omega =\sqrt{\frac{k}{m}}$

$10.362 =\sqrt{\frac{k}{0.041}}$

Squaring both side

$107.371 ={\frac{k}{0.041}}$

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For vertical osculation

$mg=kA$

$0.041\times 9.8=4.40\times A$

A = 0.091 m

So amplitude will be equal to 0.0391 m

8 0

2 years ago