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Studentka2010 [4]
4 years ago
10

Which body have a period of revolution of 29.6 days?

Physics
2 answers:
Kaylis [27]4 years ago
6 0
It would be C the moon because the total of all positions (new moon, first quarter, third quarter, full moon, waxing crescent, waning crescent, waxing gibbous, waning gibbous) of the moon would take about 29.6 days on a regular calendar. I hope this helps. :)
adelina 88 [10]4 years ago
4 0
The moon is the closest one on the list. Its period of revolution around the Earth is 27.32 days. (But the length of the cycle of phases, like from one Full Moon to the next one, is 29.53 days.)
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A boat has a mass of 6800 kg. its engines generate a drive force of 4100 n, due west, while the wind exerts a force of 830 n, du
erastova [34]

 Let positive be west and negative be east because they are contrasting in directions.

 
The forces are 4100, -830, and -1200

 
The sum of the forces is 4100 – 830 – 1200 = 2070 N. 

Newton’s law F = ma is used. 
2070 = 6800 a 

Isolating a will give us 2070 / 6800 = a

a = 0.34 m/s^2

5 0
3 years ago
Suppose a radio signal (light) travels from Earth and through space at a speed of 3 × 108/ (this is the speed of light in vacuum
Umnica [9.8K]

Answer:

18*10^10 meters

Explanation:

V= d/t         10 mins = 600 seconds

3*10^8 = d/600s

(3*10^8)*(6*10^2) = d

d = 18*10^10 m

6 0
4 years ago
An airplane cruises at 850 km/h relative to the air. It is flying from Denver, Colorado, due west to Reno, Nevada, a distance of
skad [1K]

Answer:

difference in flight time= 0.3023 hour

Explanation:

The question is incomplete, but I found it in your textbook.

Spped of aircraft = 850 km/h

Opposing speed of wind = 90km/h

Hence, the net speed when it's travelling west = 850 - 90 = 760 km/hr

The distance covered = 1200km

time taken = distance/ time = 1200/ 760 = 1.5789 hours

When coming back, the speed of the wind is complementary to the speed of the aircraft so

net speed when it's coming back = 850 +90 = 940 km/hr

time taken in this instance = 1200/ 940 = 1.2765 hours

Hence, the difference in flight time= 1.5789 - 1.2765 = 0.3023 hour

8 0
3 years ago
Astronauts aboard the ISS move at about 8000 m/s, relative to us when we look upward.How long does an astronaut need to stay abo
Luba_88 [7]

Answer:

#_time = 7.5 10⁴ s

Explanation:

In order for the astronaut to be younger than the people on earth, it follows that the speed of light has a constant speed in vacuum (c = 3 108 m / s), therefore with the expressions of special relativity we have.

            t = \frac{t_p}{ \sqrt{1-  (v/c)^2} }

where t_p is the person's own time in an immobile reference frame,

           t_{p} = t \sqrt{1 - (\frac{v}{c})^2 }

let's calculate

we assume that the speed of the space station is constant

              t_p = 1 \sqrt{1 - \frac{8 \ 10^3}{3 \ 10^8} }

             t_p = 1 \sqrt{1- 2.6666 \ 10^{-5}}

             t_ =  0.99998666657   s

             

therefore the time change is

             Δt = t - t_p

             Δt = 1 - 0.9998666657                  

              Δt = 1.3333 10⁻⁵ s

this is the delay in each second, therefore we can use a direct rule of proportions. If Δt was delayed every second, how much second (#_time) is needed for a total delay of Δt = 1 s

               #_time = 1 / Δt

               #_time =\frac{1}{1.3333 \ 10^{-5}}

               #_time = 7.5 10⁴ s

5 0
3 years ago
How does the wave model of electrons orbiting the nucleus account for discrete energy values?
o-na [289]

Explanation:

When treating the electron as a wave, the concept of electrons orbiting the nucleus allows for the distinct energy levels.The diameter of electron orbits matches the orbit radii which also discrete the energy levels.

The small number of deflected particles were repelled from powerful heavy positively charged central cores which is known as the atomic nucleus.

8 0
3 years ago
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