Answer:
the speed of something in a given direction
Explanation:
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Answer:
m = 50 [kg]
Explanation:
The potential energy can be calculated by means of the following equation.

where:
Ep = potential energy = 735 [J]
m = mass [kg]
g = gravity acceleration = 9.81 [m/s²]
h = elevation = 1.5 [m]
Now replacing:
![735=m*9.81*1.5\\m = 50 [kg]](https://tex.z-dn.net/?f=735%3Dm%2A9.81%2A1.5%5C%5Cm%20%3D%2050%20%5Bkg%5D)
Answer:
76.0198 rev/sec
Explanation:
Given
Torque ( T ) = 29.1 N
Moment of inertia = 0.142 kg.m²
Ф = 14.1 rev
F = 

F = T ΔФ
w² =( 2TΔФ)/I =
w = √5779.01 = 76.0198 rev/sec
Answer:
(a) x = 0.25 m
(b) v = 1.46 m/s
(c) v = 2.4 m/s
Explanation:
mass (m) = 10.3 kg
force from thrust (F) = 240 N
spring constant (k) = 400 N/m
stretch distance from thrust (y) = 30 cm = 0.3 m
acceleration due to gravity (g) = 9.8 m/s^{2}
(A) from mg = kx
compression (x) = mg/ k
x = 
x = 0.25 m
(B) from the conservation of forces
(Fy) + (0.5k
) = (0.5k
) + mgh + (0.5m
)
v =
) - (0.5k
) - mgh }{0.5m}[/tex]}[/tex]
v =
) - (0.5 x 400 x
) - (10.3 x 9.8 x (0.25 + 0.3)) }{0.5 x 10.3}[/tex]}[/tex]
v = 1.46 m/s
(C) if the rocket weren't attached to the spring, the conservation of energy equation becomes
(Fy) + (0.5k
) = mgh + (0.5m
)
v =
) - mgh }{0.5m}[/tex]}[/tex]
v =
) - (10.3 x 9.8 x (0.25 + 0.3)) }{0.5 x 10.3}[/tex]}[/tex]
v = 2.4 m/s