Answer:
The possible lengths of the garden are 57.32 feet and 22.68 feet
Step-by-step explanation:
We all know that the perimeter of a rectangle is the addition of the length and the base multiplied by 2(ie [L×W]2).
If the perimeter of the rectangular garden is 160 feet and its area is 1300 square feet,we can get the lenght and the width of that particular garden having the shape of a rectangle.
Let's assume the lenght of the rectangle as X
And it's width as Y,we will have something that looks like this if we apply the area and perimeter
X × Y = 1300____________ equation 1
(X + Y) × 2 = 160
~ 2X + 2Y = 160_________ equation 2
From equation 1,we make x the subject of the formula so as to find x
X = 1300/Y
Substitute "X = 1300/Y in equation 2
2(1300/Y) + 2Y = 160
Open up the bracket above
2600/Y + 2Y = 160
(2600 + 2Y²)/Y = 160
2600 + 2Y² = 160y
2Y² - 160Y + 2600 = 0
Factorize the above quadratic equation and we have
y = 57.32 or 22.68 feet's.
The width will be 22.68 feet since its the smaller figure of the 2 figures
AND the length will be 57.32 feet.
Now let's check to see if we are correct about the figures we got.
Remember that the area of the rectangle is length × width
57.32 × 22.68 = 1300 square feet.
And the perimeter which is 2L + 2W
114.64 + 45.36 = 160 feet