The interval that f(x) is increasing is the distance from 200 to 300.
The minimum value of f(x) in the interval 0<x<300 is 200.
At a value of 500, the value of f(x) is 0.
The function can't be a quadratic function since there are two points in the graph where f(x) changes its rate from increasing to decreasing or the opposite. A quadratic function has only one of that point.
We can solve this using substitution.
because x-y=2.5
x=y+2.5
Now substitute x into other equation.
2(y+2.5)^2-2y=125
2y^2+10y+12.5-2y=125
2y^2+8y-112.5=0
Now comes the ugly part
y=-4+-sqrt(16+900)
y=-4+-sqrt916
y=-4+-2sqrt229
x=-1.5+-2sqrt229
Answer:
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Step-by-step explanation:
839/41=20.4634146341
Answer:
Step-by-step explanation:
We want to simplify:
We convert to improper fraction to get:
We now deal with the parenthesis by multiplying with the reciprocal of 2.
This gives:
We multiply to get:
This simplfies to:
We write as mixed number
