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3 years ago

Where would you except to find the center of gravity of a plastic ruler

1 answer:

3 0

You would expect to find the center of gravity in a ruler in the middle because if you were to cut a ruler in half, depending on the center of gravity, you would have two equal pieces, which mean there is equal weight, meaning the middle is the center of gravity

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6. A 2.2 kg rock rests on the edge of a bridge that is 3.3 m above a river. What is the

vovikov84 [41]

Answer: 71 J

Explanation: The formula for gravitational potential energy is Epg= mgh.

So you plug in 2.2 as m, 3.3 as h and 9.81 as g. Once you do that you should get an answer of 71.2206. But because there are only two significant digits in the question, your answer must also have two significant digits.

6 0

3 years ago

A truck travels due east for a distance of 1.9 km, turns around and goes due west for 8.7 km, and finally turns around again and

Hatshy [7]

Answer:

a) Total distance travelled = 1.9km + 8.7km + 3.0km = 13.6km

b) Total displacement = -1.9km + 8.7km-3.0km=+3.8km

Total displacement = 3.8km due west

Explanation:

a) Total distance travelled is a scalar quantity it is not affected by the direction it's only concerned with the magnitude.

Total distance travelled = 1.9km + 8.7km + 3.0km = 13.6km

b) Total displacement is a vector quantity it takes into consideration both magnitude and direction.

Taking west as positive and east as negative.

Total displacement = -1.9km + 8.7km-3.0km = +3.8km

Total displacement = 3.8km due west

8 0

3 years ago

During a solar eclipse, the Moon, Earth, and Sun all lie on the same line, with the Moon between the Earth and the Sun.

lord [1]

Answer:

(a) $F_{sm} = 4.327\times 10^{20}\ N$

(b) $F_{em} = 1.983\times 10^{20}\ N$

Solution:

As per the question:

Mass of Earth, $M_{e} = 5.972\times 10^{24}\ kg$

Mass of Moon, $M_{m} = 7.34\times 10^{22}\ kg$

Mass of Sun, $M_{s} = 1.989\times 10^{30}\ kg$

Distance between the earth and the moon, $R_{em} = 3.84\times 10^{8}\ m$

Distance between the earth and the sun, $R_{es} = 1.5\times 10^{11}\ m$

Distance between the sun and the moon, $R_{sm} = 1.5\times 10^{11}\ m$

Now,

We know that the gravitational force between two bodies of mass m and m' separated by a distance 'r' is given y:

$F_{G} = \frac{Gmm'_{2}}{r^{2}}$ (1)

Now,

(a) The force exerted by the Sun on the Moon is given by eqn (1):

$F_{sm} = \frac{GM_{s}M_{m}}{R_{sm}^{2}}$

$F_{sm} = \frac{6.67\times 10^{- 11}\times 1.989\times 10^{30}\times 7.34\times 10^{22}}{(1.5\times 10^{11})^{2}}$

$F_{sm} = 4.327\times 10^{20}\ N$

(b) The force exerted by the Earth on the Moon is given by eqn (1):

$F_{em} = \frac{GM_{s}M_{m}}{R_{em}^{2}}$

$F_{em} = \frac{6.67\times 10^{- 11}\times 5.972\times 10^{24}\times 7.34\times 10^{22}}{(3.84\times 10^{8})^{2}}$

$F_{em} = 1.983\times 10^{20}\ N$

$F_{se} = \frac{GM_{s}M_{m}}{R_{es}^{2}}$

$F_{se} = \frac{6.67\times 10^{- 11}\times 1.989\times 10^{30}\times 5.972\times 10^{24}}{((1.5\times 10^{11}))^{2}}$

$F_{se} = 3.521\times 10^{20}\ N$

7 0

3 years ago

A wooden block has a mass of 986 g and a density of 16 g/ cm3. What is the volume?

netineya [11]

Density = Mass / Volume.
Volume = Mass / Density = 986 / 16 = 61.625 cm^3.

3 0

3 years ago

Mary slides down a snow-covered hill on a large piece of cardboard and then slides across a frozen pond at a constant velocity o

Sophie [7]

Explanation is in the file

tinyurl.com/wtjfavyw

8 0

3 years ago