A. very small objects behave like like particles.
From rest, a rock is dropped from a garage roof. The roof is 6.0 meters above ground level. The rock will reach the earth at a speed of 10.849 meters per second.
<h3>What is velocity?</h3>
The change of displacement with respect to time is defined as the velocity. Velocity is a vector quantity.
it is a time-based component. Velocity at any angle is resolved to get its component of x and y-direction.
Given data:
V(Final velocity)=? (m/sec)
h(height)= 6.0 m
u(Initial velocity)=0 m/sec
g(gravitational acceleration)=9.81 m/s²
Newton's third equation of motion:

Hence, the velocity of the rock as it hits the ground will be 10.849 m/sec.
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Answer:
60 kg m/s
Explanation:
Let
be the acceleration of the object.
As the acceleration of the object is constant, so

Given that applied force, F=6.00 N,
From Newton's second law, we have
,
[from equation (i)]


[given that time, t=10 s and F=6 N]

Here mv is the final momentum of the object and mu is the initial momentum of the object.
So, the change in the momentum of the object is mv-mu.
Hence, the change in the momentum of the object is 60 kg m/s.
Answer:
From shortest wavelength to longest wavelength:
Gamma Rays
X-Rays
Ultraviolet
Visible Light
Infrared waves
Microwaves
Radio Waves
Explanation:
Yes because you intoxicated
Hope this helped :)