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3 years ago

What does an octopus have to do with why atoms bond with other atoms?

Physics

1 answer:

Ierofanga [76]3 years ago

5 0

Answer:

Atoms make their exterior electron shells more robust. They shape chemical connexions. There was a misunderstanding. If one atom is stable by removing the exterior electrons, the other atoms (typically by filling their valence shell), by obtaining electrons, form an ionic relationship where one atom effectively gives another an electron.

Explanation:

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5. One of the attractions at Typhoon Lagoon, a water park in Florida, is a surf

tino4ka555 [31]

Answer:

1595790 gallons

Explanation:

Given that;

3.8 L = 1 US gallon

303,200.0 liters = 303,200.0 * 1/ 3.8 = 79789.5 gallons

If a wave is made every 90 seconds which is 1.5 mins

Then;

Number of waves made in 30 minutes = 30/1.5 = 20 waves

if each uses 79789.5 gallons, then 20 waves will use 20 * 79789.5 gallons = 1595790 gallons

3 0

3 years ago

you happen to visit the moon when some people on earth see a total solar eclipse. who has a better experience of this event, you

Vinil7 [7]

The friends left on earth because they can see the total eclipse, where as you are on the moon witnessing sections get dark rather than the whole picture

5 0

3 years ago

F F= {mango, apple, banana, orange)

Stels [109]

Answer:

Explanation:

Cardinality of a set is the number of elements in that set. Given the set.

F= {mango, apple, banana, orange), we are to determine the cardinality of the set i.e the amount of fruit present in the set. Cardinality of the set F is represented as n(F).

Since there are 4 different fruit in the given set F, hence the cardinality of the set F is n(F) = 4

6 0

4 years ago

A proton orbits a long charged wire, making 1.80 ×106 revolutions per second. The radius of the orbit is 1.20 cm What is the wir

Fantom [35]

Answer:

linear charge density = -9.495 × $10^{-34}$ C/m

Explanation:

given data

revolutions per second = 1.80 × $10^{6}$

radius = 1.20 cm

solution

we know that when proton to revolve around charge wire then centripetal force is require to be in orbit of radius around provide by electric force

- q × E = m × w² × r ..................1

- 9 × $10^{9}$ × $\frac{2*linear\ charge\ density}r}$ q = m × w² × r ............2

and w = $\frac{2*\pi}{T}$

w = $\frac{d\theta }{dt}$

w = 1.80 × $10^{6}$ × $\frac{2*\pi}{1}$

w = 11304000 rad/s

so here from equation 2

- 9 × $10^{9}$ × $\frac{2*linear\ charge\ density}{0.012}$ 1.80 × $10^{6}$ = 1.672 × $10^{-27}$ × 11304000² × 0.0120

linear charge density = -9.495 × $10^{-34}$ C/m

8 0

3 years ago

The electric field in a region of space increases from 0 to 2150 N/C in 5.00 s. What is the magnitude of the induced magnetic fi

Feliz [49]

To solve this problem we will use the Ampere-Maxwell law, which describes the magnetic fields that result from a transmitter wire or loop in electromagnetic surveys. According to Ampere-Maxwell law:

$\oint \vec{B}\vec{dl} = \mu_0 \epsilon_0 \frac{d\Phi_E}{dt}$

Where,

B= Magnetic Field

l = length

$\mu_0$ = Vacuum permeability

$\epsilon_0$ = Vacuum permittivity

Since the change in length (dl) by which the magnetic field moves is equivalent to the perimeter of the circumference and that the electric flow is the rate of change of the electric field by the area, we have to

$B(2\pi r) = \mu_0 \epsilon_0 \frac{d(EA)}{dt}$