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lions [1.4K]
3 years ago
7

A charge is moving in a magnetic field that points to the left. What direction can the charge move and experience no magnetic fo

rce? Check all that apply A. up B. down C. left D. right E. into the screen F. out of the screen .
What must be known to determine the direction of the magnetic force on a charge? Check all that apply. A. the type of the charge B. the amount of the charge C. the direction of the magnetic field D. the velocity of the charge E. the strength of the magnetic field
Physics
2 answers:
dlinn [17]3 years ago
7 0

its c and d fam \(-u-)/

tiny-mole [99]3 years ago
4 0
The answer is left and right. 
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Dont be rude she's asking you that the question Ugh 
Oh and the answer is Liquid water even though water is already liquid ok its just water okay
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3 years ago
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A thermometer is placed in water in order to measure the water’s temperature. What would cause the liquid in the thermometer to
klemol [59]
<span>The molecules in the thermometer’s liquid spread apart.  (B)</span>
3 0
3 years ago
Let’s allow ourselves to be a little more optimistic with our bus passengers. Earlier in the movie Sandy has to make the bus jum
Roman55 [17]

Answer:

25.71486 seconds

Explanation:

t = Time taken

u = Initial velocity = 60 mph

v = Final velocity = 80 mph

s = Displacement = 0.5 mile

a = Acceleration

Converting to m/s

60\times \dfrac{1609.34}{3600}=26.8223\ m/s

80\times \dfrac{1609.34}{3600}=35.7631\ m/s

From equation of motion

v^2-u^2=2as\\\Rightarrow a=\dfrac{v^2-u^2}{2s}\\\Rightarrow a=\dfrac{35.7631^2-26.8223^2}{2\times \dfrac{1609.34}{2}}\\\Rightarrow a=0.34769\ m/s^2

v=u+at\\\Rightarrow t=\dfrac{v-u}{a}\\\Rightarrow t=\dfrac{35.7631-26.8223}{0.34769}\\\Rightarrow t=25.71486\ s

Time taken is 25.71486 seconds

4 0
3 years ago
Can some answer 7 a and b please
pav-90 [236]

Answer:

a.After 15 second Mr Comer's speed =  1.7 m/s

b.Distance travelled by Mr.Comer in 15 seconds  =   18.75\ m

Explanation:

a. Lets recall our first equation of motion V_{f} =V_{i} + at

Now we know that V_{i} = 0.8m/s , a = 0.06\ m/s^2 and

t = 15 \ sec

Plugging the values we have.

V_{f} =V_{i} + at

V_{f} =0.8 + 0.06 \times 15

V_{f} =0.8+ 0.9

V_{f} =1.7 m/s

Then Mr.Comer's speed after 15 sec = 1.7ms^-1

b.

Lets find the distance and recall our third equation of motion.

V_{f} ^2-V{i}^2 = 2as

So s = distance covered.

Dividing both sides with 2a we have.

\frac{V_{f} ^2-V{i}^2}{2a} = 2as

Plugging the values.

\frac{(1.7)^2-(0.8)^2}{2\times0.06} = 2as

s= 18.75\ m

So Mr.Comer will travel a distance of s= 18.75\ m.

4 0
3 years ago
Which of the following does NOT represent Newton’s second law? Question 20 options: a = m/Fnet m = Fnet/a Fnet = ma a = Fnet/m
Natali [406]

Answer:

a=m/f is not an equation under newton's second law

Explanation:

newton's second law of motion is represented using: f=ma

where a=v-u/t

therefore it becomes,f=m(v-u)/t

from f=ma,

a will become f/m,

m will become f/a

8 0
2 years ago
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