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dmitriy555 [2]
3 years ago
15

What are two ways in which the suns energy can be captured and used?

Physics
2 answers:
Nezavi [6.7K]3 years ago
8 0
It can be used by giving you energy and buring calories
My name is Ann [436]3 years ago
7 0

The oldest way ... the way we've been using as long as we've been
walking on the Earth ... has been to use plants.  Plants sit out in the
sun all day, capturing its energy and using it to make chemical compounds. 
Then we come along, cut the plants down, and eat them.  Our bodies
rip the chemical compounds apart and suck the solar energy out of them,
and then we use the energy to walk around, sing, and play video games.  

Another way to capture the sun's energy is to build a dam across a creek
or a river, so that the water can't flow past it.  You see, it was the sun's
energy that evaporated the water from the ocean and lifted it high into
the sky, giving it a lot of potential energy.  The rain falls on high ground,
up in the mountains, so the water still has most of that potential energy
as it drizzles down the river to the ocean.  If we catch it on its way, we
can use some of that potential energy to turn wheels, grind our grain,
turn our hydroelectric turbines to get electrical energy ... all kinds of jobs. 

A modern, recent new way to capture some of the sun's energy is to use
photovoltaic cells.  Those are the flat blue things that you see on roofs
everywhere.  When the sun shines on them, they convert some of its
energy into electrical energy.  We use some of what they produce, and
we store the rest in giant batteries, to use when the sun is not there.
 
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Jenny was applying her makeup when she drove into the student parking lot last Friday morning . Unaware that Cheryl was stopped
Akimi4 [234]

Answer: F = 102141N

Explanation: <em><u>Newton's 2nd Law</u></em> states that a force can change the motion of a body. The relation is given by

F = m.a

whose units are:

[F] = N

[m] = kg

[a] = m/s²

Jenny's car, at the moment of the break, had acceleration:

a=\frac{\Delta v}{\Delta t}

a=\frac{11}{0.14}

a = 78.57 m/s²

Then, Force is

F = 1300*78.57

F = 102141 N

<u>Jenny's car experienced a force of </u><u>magnitude 102141N.</u>

6 0
3 years ago
Which is a consequence of the third law of thermodynamics Energy is not always conserved. Engines cannot discharge waste heat. H
miss Akunina [59]
Heat engines are less than 100% efficient because absolute zero cannot be reached
8 0
4 years ago
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A boat travels at 30 mph for a huge, solid cliff that is about 3,000 meters away. When the horn on the boat makes a toot, you ca
AleksandrR [38]

Answer:The frequency of the echo is slightly decreased

Explanation:

Given

speed of boat =30\ mph

cliff is 3000\ m away

when boat is still , suppose t is the time taken by the echo to reach observer on the boat

But as soon as boat starts moving  the distance between cliff and boat decreasing and time for echo to reach observer also decreases

and we know time \propto \frac{1}{frequency}

therefore frequency of the echo slightly decreased.

5 0
3 years ago
An automobile with passengers has weight 19.4 kN and is moving at 108 km/h when the driver brakes to a stop. The frictional forc
mixer [17]

Answer:

12.0

Explanation:

4 0
3 years ago
A drowsy cat spots a flowerpot that sails first up and then down past an open window. the pot was in view for a total of 0.49 s,
Alika [10]

For this case, let's assume that the pot spends exactly half of its time going up, and half going down, i.e. it is visible upward for 0.245 s and downward for 0.245 s. Let us take the bottom of the window to be zero on a vertical axis pointing upward. All calculations will be made in reference to this coordinate system. <span>

An initial condition has been supplied by the problem: 

s=1.80m when t=0.245s 

<span>This means that it takes the pot 0.245 seconds to travel upward 1.8m. Knowing that the gravitational acceleration acts downward constantly at 9.81m/s^2, and based on this information we can use the formula:

s=(v)(t)+(1/2)(a)(t^2) 

to solve for v, the initial velocity of the pot as it enters the cat's view through the window. Substituting and solving (note that gravitational acceleration is negative since this is opposite our coordinate orientation): 

(1.8m)=(v)(0.245s)+(1/2)(-9.81m/s^2)(0.245s)^2 

v=8.549m/s 

<span>Now we know the initial velocity of the pot right when it enters the view of the window. We know that at the apex of its flight, the pot's velocity will be v=0, and using this piece of information we can use the kinematic equation:

(v final)=(v initial)+(a)(t) 

to solve for the time it will take for the pot to reach the apex of its flight. Because (v final)=0, this equation will look like 

0=(v)+(a)(t) 

Substituting and solving for t: 

0=(8.549m/s)+(-9.81m/s^2)(t) 

t=0.8714s 

<span>Using this information and the kinematic equation we can find the total height of the pot’s flight:

s=(v)(t)+(1/2)(a)(t^2) </span></span></span></span>

s=8.549m/s (0.8714s)-0.5(9.81m/s^2)(0.8714s)^2

s=3.725m<span>

This distance is measured from the bottom of the window, and so we will need to subtract 1.80m from it to find the distance from the top of the window: 

3.725m – 1.8m=1.925m</span>

 

Answer:

<span>1.925m</span>

3 0
3 years ago
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