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ddd [48]
3 years ago
5

A plane accelerates to a velocity of 240 m/s in 11 s by which time it had traveled 1,400 m down the runway what were it average

and initial velocities
Physics
1 answer:
Alex Ar [27]3 years ago
5 0

The average velocity is 127.27 m/s while the initial velocity is 14.55 m/s

According to Newton's law of motion:

s = [(v + u)/2]t

Where s is the distance moved = 1400 m, v is the final velocity = 240 m/s, u is the initial velocity, t is the time taken = 11 s, hence:

1400 = [(240 + u)/2)11

2800 = (240 + u)11

u + 240 = 254.55

u = 14.55 m/s

The average velocity = (v + u)/2 = (240 + 14.55)/2 = 127.27 m/s

Therefore the average velocity is 127.27 m/s while the initial velocity is 14.55 m/s

Find out more at: brainly.com/question/13639113

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Explanation:

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A truck is carrying a refrigerator as shown in the figure. The height of the refrigerator is 158.0 cm, the width is 60.0 cm. The
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In order for the refrigerator not to tip over, the maximum acceleration of  1.86 m/s² must not be exceeded.

<h3>What is acceleration?</h3>

The term acceleration has to do with the rate at which velocity changes with time.

We have to take the moments at the tipping point of rotation as follows;

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F₂ * 1.58 m = F₁ * 0.67 m

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m * a * 1.58 = m * 9.81 * 0.30

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In order for the refrigerator not to tip over, the maximum acceleration of  1.86 m/s² must not be exceeded.

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5 0
2 years ago
Which of the examples below represents velocity correctly
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D

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A model rocket is launched straight upward with an initial speed of 50.0 m/s. It accelerates with a constant upward acceleration
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In the question where as a model rocket is launched straight upward with an initial speed of 50.0m/s and it accelerate with a constant acceleration of 2m/s^2 until it engines stop at an altitude od 150. So the following are the answer to your question:
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A certain moving electron has a kinetic energy of 1.01 × 10−19 J. Calculate the speed necessary for the electron to have this en
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Answer:

Velocity of electron will be equal to v=4.711\times 10^5m/sec

Explanation:

We have given kinetic energy of electron KE=1.01\times 10^{-19}J

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Kinetic energy of electron is equal to KE=\frac{1}{2}mv^2, here m is mass and v is velocity

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