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AVprozaik [17]
3 years ago
6

A block of mass 0.260 kg is placed on top of a light, vertical spring of force constant 5 200 N/m and pushed downward so that th

e spring is compressed by 0.090 m. After the block is released from rest, it travels upward and then leaves the spring. To what maximum height above the point of release does it rise
Physics
1 answer:
abruzzese [7]3 years ago
4 0

After being released, the restoring force exerted by the spring performs

1/2 (5200 N/m) (0.090 m)² = 12.06 J

of work on the block. At the same time, the block's weight performs

- (0.260 kg) <em>g</em> (0.090 m) ≈ -0.229 J

of work. Then the total work done on the block is about

<em>W</em> ≈ 11.83 J

The block accelerates to a speed <em>v</em> such that, by the work-energy theorem,

<em>W</em> = ∆<em>K</em>   ==>   11.83 J = 1/2 (0.260 kg) <em>v</em> ²   ==>   <em>v</em> ≈ 9.54 m/s

Past the equilibrium point, the spring no longer exerts a force on the block, and the only force acting on it is due to its weight, hence it has a downward acceleration of magnitude <em>g</em>. At its highest point, the block has zero velocity, so that

0² - <em>v</em> ² = -2<em>gy</em>

where <em>y</em> is the maximum height. Solving for <em>y</em> gives

<em>y</em> = <em>v</em> ²/(2<em>g</em>) ≈ 4.64 m

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A trombone plays a C3 note. If the speed of sound in air is 343 m/s and the wavelength of this note is
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The frequency of note C3 is 131 s^{-1}.

<u>Explanation:</u>

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And frequency is the completion of number of cycles in a given time in sound waves. The frequency and wavelength are inversely proportional to each other with velocity of sound being the proportionality constant.

Thus, here the speed of sound is given as 343 m/s, the wavelength of the note is also given as 2.62 m, then frequency will be as follows:

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Thus,

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A frog is at the bottom of a 17-foot well. Each time the frog leaps, it moves up 3 feet. If the frog has not reached the top of
docker41 [41]

Answer:

The frog takes 8 jumps to reach top of well

Explanation:

Given data

Frog at bottom=17 foot

Each time frog leaps 3 feet

Frog has not reached the top of the well, then the frog slides back 1 foot

To Find

Total number of leaps the frog needed to escape from well

Solution

in 1 jump distance jumped=3+(-1)

                                           =2 feet

                                           =2×1 feet

The "-1" is because the frog goes back

Now After 2 jumps the distance jumped as:

                     Distance Jumped=2+2

                     Distance Jumped=2*2

                                                   =4 feet

Similarly after 7 jumps

                    Distance Jumped=2+2+......+2

                    Distance Jumped=2*7

                                                 =14 feet

Now after 8th jump the frog climbs but doesnot slide back as it is reached to the top of well.

So

              Distance Jumped=(Distance Jumped after 7 jumps)+3

                                           =14+3

                                           =17 feet

The frog takes 8 jumps to reach top of well                

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