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umka2103 [35]
3 years ago
5

A frictionless pulley system connects a 150 Kg block of a flat surface with a coefficient of friction of 0.20 to a hanging 200 k

g block. Determine the tension on the cord, the frictional force of the block on the surface, acceleration of descending block, and time required for a hanging block to full 10 meters.
Physics
2 answers:
Feliz [49]3 years ago
5 0

Answer:

13

Explanation:

irakobra [83]3 years ago
3 0
Cuáles son los dos tipos de lípidos que se pueden encontraren la sangre
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How much energy must be absorbed by water with a mass of 0.5 kg in order to raise the temperature from 30°C to 65°C? Note: Water
kvasek [131]

Answer:

73325J

Explanation:

Given parameters:

Mass of water  = 0.5kg

Initial temperature  = 30°C

Final temperature  = 65°C

Specific heat capacity  = 4190J/kg°C

Unknown:

Amount of energy absorbed = ?

Solution:

The amount of energy absorbed can be derived using the expression below;

                H  = m c Δt

H is the amount of energy

m is the mass

c is the specific heat

Δt is the change in temperature

      H  = 0.5 x 4190 x (65 - 30 )

     H  = 73325J

6 0
3 years ago
Can some help with this? id appreciate your help :)
Slav-nsk [51]

Answer:

I am not really sure but i think its option 2

Explanation:

6 0
2 years ago
Which is the correct order of events at a power plant?
GalinKa [24]
The correct answer is A.

A power station works on the principle of boiling water to create steam, which turns a turbine, generating a potential difference in a transformer with the magnets. The transformer is connected to a circuit, which hence induces a current, generating power.
4 0
3 years ago
Read 2 more answers
A spring is hung from the ceiling. When a block is attached to its end, it stretches 2.6 cm before reaching its new equilibrium
Kaylis [27]

Answer:

f = 3.09 Hz

Explanation:

This is a simple harmonic motion exercise where the angular velocity is

         w² = \frac{k}{m}

to find the constant (k) of the spring, we use Hooke's law with the initial data

         F = - kx

where the force is the weight of the body that is hanging

        F = W = m g

we substitute

        m g = - k x

        k = - \frac{m g}{x}

we calculate

        k = - \frac{9.8 m}{- 2.6 \ 10^{-2}}

        k = 3.769 10² m

we substitute in the first equation

       w² = \frac{ 3.769 \ 10^2 \ m }{m}

       w = 19.415 rad / s

angular velocity and frequency are related

       w = 2πf

        f = \frac{w}{2\pi }

        f = 19.415 / 2pi

        f = 3.09 Hz

7 0
2 years ago
When a 2.40-kg object is hung vertically on a certain light spring described by Hooke's law, the spring stretches 2.92 cm.(a) Wh
Anastasy [175]

Answer:

805.48N/m

Explanation:

According to Hookes law

F = Ke

F is the force = mg

F = 2.4×9.8 = 23.52N

e is the extension = 2.92cm = 0.0292m

Force constant K = F/e

K = 23.52/0.0292

K = 805.48N/m

Hence the force constant of the spring is 805.48N/m

3 0
2 years ago
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