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umka2103 [35]
3 years ago
5

A frictionless pulley system connects a 150 Kg block of a flat surface with a coefficient of friction of 0.20 to a hanging 200 k

g block. Determine the tension on the cord, the frictional force of the block on the surface, acceleration of descending block, and time required for a hanging block to full 10 meters.
Physics
2 answers:
Feliz [49]3 years ago
5 0

Answer:

13

Explanation:

irakobra [83]3 years ago
3 0
Cuáles son los dos tipos de lípidos que se pueden encontraren la sangre
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Mathew throws a ball straight up into the air. It rises for a period of time and then begins to drop. At which points in the bal
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Starting from rest, a car undergoes a constant acceleration of 6 m/s^2. How far will the car travel in the two seconds?
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4 0
2 years ago
An object is released from rest and falls in free fall motion. The speed v of the object after it has fallen a distance y is giv
konstantin123 [22]

Answer:

8.91 %

Explanation:

Since v² = 2gy

By the relative error formula,

2Δv/v = Δg/g + Δy/y multiplying by 100%, we have

2Δv/v × 100% = Δg/g × 100 % + Δy/y × 100%

2(Δv/v × 100%) = Δg/g × 100 % + Δy/y × 100%

Δg/g × 100 % = 2(Δv/v × 100%) - Δy/y × 100%

Since Δv/v × 100% = 3.69 % and Δy/y × 100% = 5 %

Since we have a difference for the percentage error in g, we square the percentage errors and add them together. So,

[Δg/g × 100 %]² = [2(Δv/v × 100%)]² + [Δy/y × 100%]²

[Δg/g × 100 %]² = [2(3.69)]² + [5%]²

[Δg/g × 100 %]² = [4)(3.69 %)² + [5%]²

[Δg/g × 100 %]² = 54.4644 %² + 25%²

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taking square-root of both sides, we have

[Δg/g × 100 %] = 8.91 %

So, the percent uncertainty in the calculated value of g is 8.91 %

6 0
3 years ago
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