A frictionless pulley system connects a 150 Kg block of a flat surface with a coefficient of friction of 0.20 to a hanging 200 k
2 answers:
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Answer:
The magnitude of the electric field are and
Explanation:
Given that,
Radius of inner shell = 11.0 cm
Radius of outer shell = 14.0 cm
Charge on inner shell
Charge on outer shell
Suppose, at r = 11.5 cm and at r = 20.5 cm
We need to calculate the magnitude of the electric field at r = 11.5 cm
Using formula of electric field
Where, q = charge
k = constant
r = distance
Put the value into the formula
The total charge enclosed by a radial distance 20.5 cm
The total charge is
Put the value into the formula
We need to calculate the magnitude of the electric field at r = 20.5 cm
Using formula of electric field
Put the value into the formula
Hence, The magnitude of the electric field are and
Answer:
The amount of potential energy that was initially stored in the spring is 88.8 J.
Explanation:
Given that,
Mass of block = 1.60 kg
Angle = 30.0°
Distance = 6.55 m
Speed = 7.50 m/s
Coefficient of kinetic friction = 0.50
We need to calculate the amount of potential energy
Using formula of conservation of energy between point A and B
Put the value into the formula
Hence, The amount of potential energy that was initially stored in the spring is 88.8 J.