We're told that the planets have EQUAL MASS.
If that's true, then the strength of the gravitational forces between
each planet and the star depends only on the distance between
them ... the farther a planet is from the star, the smaller the
gravitational forces are IF we're talking about planets with
equal masses.
Planet-X is closer to the star, and Planet-Y is farther from it.
From this we know that the gravitational forces between the
star and Planet-X are greater, and the forces between the star
and Planet-Y are smaller.
'A' says this.
'B' is totally absurd, because it talks about gravity repelling things.
'C' says exactly the opposite for the two planets.
'D' says that distance doesn't matter. We know this is absurd,
simply because we're never pulled toward Jupiter in our daily life.
In the case of straight line, when the object is not repeating it's path then distance and displacement would be same.
Answer:
The trucker should drive at a speed of 11 m/s m/s
Explanation:
mass of the small car, m₁ = 795 kg
initial velocity of the small car, u₁ = 35 m/s(due east)
Mass of the truck, m₂ = 3360 kg
Initial velocity of the truck, u₂ = ?
Final velocity, V = u₁ sin37 ( the line between the camera and the collision makes an angle 37° with respect to the north)
According to the law of momentum conservation:
For the x -component
m₁u₁ = (m₁ + m₂)Vsinθ
m₁u₁ = (m₁ + m₂)Vsin37
(795*35) = (795 + 3360)* Vsin37
27825 = 2500.54V
V = 27825/2500.54
V = 11.13 m/s
For the y - component
m₂u₂ = (m₁ + m₂)Vcos37
3360*u₂ = (795+3360)*11.13*cos37
3360*u₂ =36933.02
u₂ = 36933.02/3360
u₂ = 11 m/s
-- The boiling points of the first group are all at temperatures
that are way lower than a comfortable room.
. . . . . Nitrogen . . . -320° F
. . . . . Helium . . . . -452° F
. . . . . Neon . . . . . -411° F
The freezing points of the second group are all at temperatures
that are way higher than a comfortable room.
. . . . . Lithium. . . . . . 357° F
. . . . . Sodium . . . . . 208° F
. . . . . Potassium . . . 146 °F
