Propane (C3H8), a common fuel, reacts with oxygen to form carbon dioxide and water according to the equation below: C3H8 + 5O2 →
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<u>Answer:</u> The amount of carbon dioxide gas produced in the reaction is 83.6 grams
<u>Explanation:</u>
As, some amount of oxygen gas is left after the reaction is completed. So, it is present in excess and is considered as an excess reagent.
Thus, carbon is considered as a limiting reagent because it limits the formation of product.
To calculate the number of moles, we use the equation:
.....(1)
Given mass of carbon = 22.8 g
Molar mass of carbon = 12 g/mol
Putting values in equation 1, we get:
The chemical equation for the reaction of carbon and oxygen gas follows:
By Stoichiometry of the reaction:
1 mole of carbon produces 1 mole of carbon dioxide gas
So, 1.9 moles of carbon will produce = of carbon dioxide gas
Now, calculating the mass of carbon dioxide from equation 1, we get:
Molar mass of carbon dioxide = 44 g/mol
Moles of carbon dioxide = 1.9 moles
Putting values in equation 1, we get:
Hence, the amount of carbon dioxide gas produced in the reaction is 83.6 grams