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Sonja [21]
3 years ago
7

How many milliliters of 0.183 m hcl would be required to titrate 5.93 g koh?

Chemistry
1 answer:
jek_recluse [69]3 years ago
4 0
  Molar mass:
KOH = 56.0 g/mol

Number of moles of KOH :

5.93  / 36.5 => 0.1624 moles

<span>KOH + HCl = KCl + H₂O 
</span>
1 mole KOH --------------> 1 mole  HCl
0.1624 moles KOH ----> ?

moles HCl = 0.1624 x 1 / 1

= 0.1624 moles of HCl

V ( HCl ) = moles / molarity

V(HCl) = 0.1624 / 0.183

V (HCl) = 0.887 L x 1000 = 887 mL

hope this helps!



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Given data:

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Empirical formula:

It is the simplest formula gives the ratio of atoms of different elements in small whole number

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Number of gram atoms of C = 20 / 12 = 1.7

Atomic ratio:

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           1.7/1.7                :     3.3/1.7       :       1.7/1.7

              1                     :           2          :        1

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Molecular formula:

Molecular formula = n (empirical formula)

n = molar mass of compound / empirical formula mass

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Molecular formula = 6 (CH₂O)

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