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Alex
3 years ago
14

Calculate the number of C atoms in 0.183 mol of C.

Chemistry
1 answer:
Alex Ar [27]3 years ago
4 0

Answer: 1.10x10²³ atoms of C

110202600000000000000000 atoms C

Explanation:The solution process is shown below.

0.183 mole C x 6.022x10²³ atoms C / 1 mole C

= 1.10x10²³ atoms C

or 110202600000000000000000 atoms C

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Vinvika [58]
Fe because oxidation mean loss of oxygen and Fe lose the oxygen so Fe is oxidised
7 0
3 years ago
Which of the following chemical equations is balanced?
muminat

Answer:

A, 4Fe 3O2 → 2Fe2O3

5 0
3 years ago
¿How do the products of the reaction to the phenol red test and the splint test? Please help me it's for today.! :((​
laila [671]

Answer:

The answer in this question is show you made Sodium Hydroxide and Hydrogen Gas.In order to do the products of the reaction relate to the phenol red test and the splint test you need to show that you made Sodium Hydroxide and Hydrogen Gas. Show that you made Sodium Hydroxide and Hydrogen Gas so that the products of the reaction relate to the phenol red test and the splint test.

5 0
3 years ago
The standard enthalpy change for the following reaction is 873 kJ at 298 K.
Flura [38]

Answer:  - 436.5 kJ.

Explanation:

According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.

According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation.

The given chemical reaction is,

2KCl(s)\rightarrow 2K(s)+Cl_2(g)  \Delta H_1=873kJ

Now we have to determine the value of \Delta H for the following reaction i.e,

K(s)+\frac{1}{2}Cl_2(g)\rightarrow KCl(s) \Delta H_2=?

According to the Hess’s law, if we divide the reaction by half then the \Delta H will also get halved and on reversing the reaction , the sign of enthlapy changes.

So, the value \Delta H_2 for the reaction will be:

\Delta H_2=\frac{1}{2}\times (-873kJ)

\Delta H_2=-436.5kJ

Hence, the value of \Delta H_2 for the reaction is -436.5 kJ.

8 0
3 years ago
instrucions classify the following reactions as synthesis, decomposition,single replacement, double replacement, or combustion.
My name is Ann [436]

Answer:

There are no specific equations but here what i can give you:

1. Synthesis -- A synthesis reaction is a chemical change in which two or more substances react to form a single new substance.

In all synthesis reactions, there is a single product that is a compound!

2. Decomposition -- A decomposition reaction is a chemical change in which a single compound breaks down into two or more simpler products. (This is the opposite of synthesis reactions!)

Most decomposition reactions require energy in the form of heat, light, and electricity.

3. Single Replacement -- A single-replacement reaction is a chemical change in which one element replaces a second element in a compound. You can identify a single-replacement reaction by noting that both the reactants and the products consist of an element and a compound.

4. Double Replacement -- A double-replacement reaction is a chemical change involving an exchange of positive ions between two compounds.

For a double replacement reactions to occur, one of the following is usually true:

- One of the products is only slightly soluble and precipitates from solutions.

- One of the products is a gas.

- One product is a molecular compound such as water.

5. Combustion -- A combustion reactions is a chemical change in which an element or a compound reacts with oxygen, often producing energy in the form of heat or light.

A combustion reactant always involves oxygen as a reactant. (If the supply of oxygen is limited, then the combustion will not be complete.)

The other reactant is a hydrocarbon, which is a compound composed of hydrogen and carbon and the complete combustion of a hydrocarbon produces CO2 and H2O.

Hydrocarbons include methane, propane, and butane.

I really hope this helps you!

3 0
3 years ago
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