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3 years ago

Calculate the number of C atoms in 0.183 mol of C.

Chemistry

1 answer:

Alex Ar [27]3 years ago

4 0

Answer: 1.10x10²³ atoms of C

110202600000000000000000 atoms C

Explanation:The solution process is shown below.

0.183 mole C x 6.022x10²³ atoms C / 1 mole C

= 1.10x10²³ atoms C

or 110202600000000000000000 atoms C

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32,127.02 grams of hydrogen hexafluorosilicate will contain this 25,434 grams of F.

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1.6 kilogram of fluorine per million kilograms of water. (Given)

Concentration of fluorine in water = 1.6 kg/ 1000,000 kg of water

In 1000,000 kg of water = 1.6 kg of fluorine

Then $15,896,250 kg$ of water have x mass of fluorine:

$\frac{x}{15,896,250 kg\text{kg of water}}=\frac{1.6 kg}{1000,000 \text{kg of water}}$

$x=\frac{1.6 kg}{1000,000}\times 15,896,250 kg=25.434 kg$

15,896,250 kg water of contains mass 25.434 kg of fluorine.

25.434 kg = 25434 g

25,434 grams of fluorine should be added to give 1.6 ppm.

Percentage of fluorine in hydrogen hexafluorosilicate :

Molar mass hydrogen hexafluorosilicate = 144 g/mol

$F\%=\frac{6\times 19 g/mol}{144 g/mol}\times 100=79.16\%$

Total mass of hydrogen hexafluorosilicate = m'

$79.16\%=\frac{25,434 g}{m'}\times 100$

m' = 32,127.02 g

32,127.02 grams of hydrogen hexafluorosilicate will contain this 25,434 grams of F.

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