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o-na [289]
2 years ago
13

What is the overall charge on the compound, sodium hydroxide? explain

Chemistry
1 answer:
Fiesta28 [93]2 years ago
7 0

Answer:

Overall, the electric charge of the compound {\rm NaOH} is 0.

Explanation:

Sodium hydroxide {\rm NaOH} is an ionic compound. This compound is made up of a large number of sodium ions {\rm Na^{+}} and hydroxide ions {\rm OH^{-}}.

As the superscripts suggest, each sodium ion {\rm Na^{+}} carries a charge of (+1) while each hydroxide ion {\rm OH^{-}} carries a charge of (-1).

The two types of ions are paired up at a one-to-one ratio within {\rm NaOH}. Charges on these ions would balance one another, such that the overall electric charge on the compound {\rm NaOH}\! would be 0.

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Answer:

Explanation:

1)

Given data:

Mass of lead = 25 g

Initial temperature = 40°C

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Cp = 0.0308 j/g.°C

Heat required = ?

Solution:

Specific heat capacity: Cp

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

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2)

Given data:

Mass  = 3.1 g

Initial temperature = 20°C

Final temperature = 100°C

Cp = 0.385 j/g.°C

Heat required = ?

Solution:

Specific heat capacity: Cp

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = Final temperature = initial temperature

ΔT = 100°C -  20°C

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3)

Given data:

Mass of Al = ?

Initial temperature = 60°C

Final temperature = 30°C

Cp = 0.897 j/g.°C

Heat released = 120 j

Solution:

Specific heat capacity: Cp

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = Final temperature = initial temperature

ΔT = 30°C -  60°C

ΔT = -30°C

120 j = m × 0.897 j/g.°C  × -30°C

120 j = m × -26.91  j/g

m = 120 j / -26.91  j/g

m =  4.46 g

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4)

Given data:

Mass of ice = 1.5 g

Change in temperature  = ?

Cp = 0.502 j/g.°C

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Solution:

Specific heat capacity: Cp

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = Final temperature = initial temperature

30.0 j = 1.5 g × 0.502 j/g.°C  × ΔT

30.0 j = 0.753 j/°C  × ΔT

30.0 j /0.753 j/°C  = ΔT

39.84 °C  =  ΔT

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Answer:

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