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3 years ago

In an ionic bond:

Chemistry

2 answers:

Aleks04 [339]3 years ago

6 0

A. Both atoms share their electrons

Fynjy0 [20]3 years ago

4 0

In an ionic bond :

=》B. one atom accepts electrons from another.

in this bond an atom ( metallic ) loses its electrons and another atom ( non- metallic ) accepts the electrons, and since there isn't the equal positive and negative charges in the atoms, they forms cations ( +ve charge ) and anions ( -ve charge )

and get stacked or attracted to each other by strong electrostatic force.

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I will give brainliest if answer is good

noname [10]

Microwaves use radiant energy to cook the food. They also use electrical to make the microwave work.

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4 years ago

Read 2 more answers

The distribution of Na+ ions across a typical biological membrane is 10 mmol dm-3 inside the cell and 140 mmol dm-3 outside the

trasher [3.6K]

Answer : The value of $\Delta G^o$ across the membrane is 6.80 kJ/mol

Explanation :

The relation between the equilibrium constant and standard Gibbs free energy is:

$\Delta G^o=-RT\times \ln K_{eq}\\\\\Delta G^o=-RT\times \ln (\frac{C_{in}}{C_{out}})$

where,

$\Delta G^o$ = standard Gibbs free energy = ?

R = gas constant = 8.314 J/K.mol

T = temperature = $37^oC=273+37=310K$

$K_{eq}$ = equilibrium constant

$C_{in}$ = concentration inside the cell = $10mmol.dm^{3-}$

$C_{out}$ = concentration outside the cell = $140mmol.dm^{3-}$

Now put all the given values in the above formula, we get:

$\Delta G^o=-RT\times \ln (\frac{C_{in}}{C_{out}})$

$\Delta G^o=-(8.314J/K.mol)\times (310K)\times \ln (\frac{10mmol.dm^{3-}}{140mmol.dm^{3-}})$

$\Delta G^o=6.80\times 10^{3}J/mol=6.80kJ/mol$

Thus, the value of $\Delta G^o$ across the membrane is 6.80 kJ/mol

8 0

3 years ago

Which organelle packages materials and distributes them throughout the cell?

Anastasy [175]

The golgi body i think

4 0

3 years ago

Read 2 more answers

Show the empirical formula manganese fluoride; 59.1% Mn and 40.9% F. Fill in the subscripts on the formula below. Make sure to h

Gre4nikov [31]

Hey there!:

Given % of Mn=59.1% means 59.1 g of Mn present in 100 g of manganese fluoride.

Molar mass of Mn= 54.938 g/mol

Moles of Mn = mass / molar mass

59.1 /54.938 => 1.07 ≈ 1 mol.

and % of F=40.9% means 40.9 g of of F present in 100 g of manganese fluoride.

Molar mass of F=18.998 g/mol

Moles of F :

40.9 / 18.999 => 2.15 mol ≈ 2 mol.

The mole ratio between Mn:F= 1 : 2

Therefore the empirical formula of manganese fluoride:

=> MnF2=Mn1F2

Hope that helps!

3 0

4 years ago

Read 2 more answers

12 = 3X X = 7X = 57 X = 11X = 27.7 X =

dybincka [34]

Answer:
1. $x=4$
2. $x=\frac{57}{7}$
3. $x=\frac{27.7}{11}$

Explanation:

Given the following questions:

$12=3x$
$7x=57$
$11x=27.7$

In order to find the answers to these questions, we have to recognize that in order to isolate the variable we need to divide on both sides.

Question one:
$12=3x$
$\frac{3x}{3} =\div3$
$12\div3=4$
$x=4$

Question two:
$7x=57$
$\frac{7x}{7} =\div7$
$57\div7=8.14285714=\frac{57}{7}$
$x=\frac{57}{7}$

Question three:
$11x=27.7$
$\frac{11x}{11} \div11$
$27.7\div11=2.51818182=\frac{27.7}{11}$
$x=\frac{27.7}{11}$

Hope this helps.

3 0

2 years ago