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pshichka [43]
3 years ago
13

In an ionic bond:

Chemistry
2 answers:
Aleks04 [339]3 years ago
6 0
A. Both atoms share their electrons
Fynjy0 [20]3 years ago
4 0

In an ionic bond :

=》B. one atom accepts electrons from another.

in this bond an atom ( <em><u>metallic</u></em> ) loses its electrons and another atom ( <em><u>non- metallic</u></em> ) accepts the electrons, and since there isn't the equal positive and negative charges in the atoms, they forms <em><u>cations</u></em> ( +ve charge ) and <em><u>anions </u></em>( -ve charge )

and get stacked or <em><u>attracted</u></em> to each other by strong <em><u>electrostatic force</u></em>.

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In which direction does the wind blow from during a sea breeze
Nadusha1986 [10]

Answer:

Sea breeze moves from the areas of higher pressure on the water in the direction of the areas of lower pressure on land.

Explanation:

Sea breeze moves from the areas of higher pressure on the water in the direction of the areas of lower pressure on land. Whereas, land breeze blows from the areas of higher pressure on land to the areas of lower pressure on water.

3 0
2 years ago
The solubility of o2 at 20c is 1.38 x10^-3. the partial presure of o2 in the air at sea level is 0.27 atm. using henery;s law, c
netineya [11]

<u>Answer:</u> The solubility of oxygen at 682 torr is 4.58\times 10^{-3}M

<u>Explanation:</u>

To calculate the molar solubility, we use the equation given by Henry's law, which is:

C_{A}=K_H\times p_{A}

Or,

\frac{C_{1}}{C_{2}}=\frac{p_{1}}{p_2}

where,

C_1\text{ and }p_1 are the initial concentration and partial pressure of oxygen gas

C_2\text{ and }p_2 are the final concentration and partial pressure of oxygen gas

We are given:

Conversion factor used:  1 atm = 760 torr

C_1=1.38\times 10^{-3}M\\p_1=0.27atm\\C_2=?\\p_2=682torr=0.897atm

Putting values in above equation, we get:

\frac{1.38\times 10^{-3}}{C_2}=\frac{0.27atm}{0.897atm}\\\\C_2=\frac{1.38\times 10^{-3}\times 0.897atm}{0.27atm}=4.58\times 10^{-3}M

Hence, the solubility of oxygen gas at 628 torr is 4.58\times 10^{-3}M

4 0
3 years ago
Oftentimes solubility of a compound limits the concentration of the solution that can be prepared. Use the solubility data given
bulgar [2K]

Answer:

NaNO3 (solubility = 89.0 g/100 g H2O)

Explanation:

The solubility of a specie is the amount of solute that will dissolve in one litre of the solvent. Solubility is usually expressed in units of molarity.

Now let us calculate the molarity of the NaNO3 (solubility = 89.0 g/100 g H2O)

Molar mass of NaNO3= 23+14+3(16)= 85gmol-1

Mass of solute=89.0g

Amount of solute= mass of NaNO3/molar mass of NaNO3

Amount of solute= 89.0g/85.0 gmol-1

= 1.0moles of NaNO3

Note that 100g of water=100cm^3 of water.

If 1.0 moles of NaNO3 dissolve in 100cm^3 or water therefore,

x moles of NaNO3 will dissolve in 1000cm^3 of water

x= 1.0 × 1000/ 100

x= 10.0 moles of NaNO3

3 0
3 years ago
What is relativity exactly
kiruha [24]
The absence of standards of absolute and universal application.
6 0
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hope this info helps

4 0
2 years ago
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