The less dense areas in a sound wave is called a rarefaction or rarefactions if there are multiple.
Rubidium would exhibit the greatest shielding [ effect. ]
Answer:
I think the answer is 6.022*10^23
The answer is: the rate of reaction is 850 g/min.
n(P₄O₁₀) = 1.5 mol; amount of product.
M(P₄O₁₀) = 283.9 g/mol; molar mass of phosphorus(V) oxide.
m(P₄O₁₀) = n(P₄O₁₀) · M(P₄O₁₀).
m(P₄O₁₀) = 1.5 mol · 283.9 g/mol.
m(P₄O₁₀) = 425.85 g in 30 seconds.
Make proportion: 425 g : 30 s = m(P₄O₁₀) : 60 s.
m(P₄O₁₀) = 850 g in 60 s.
Answer:
T = 82 K
Explanation:
The computation of the final temperature is shown below;
Given that
T_0 denotes the initial temperature of the gas i.e. 74 K
T denotes the final temperature of the gas = ?
n denotes number of moles of monoatomic gas i.e. 1.00 mol
R denotes universal gas constant = 8.314
c denotes the heat capacity at constant volume i.e.
= (1.5) R = (1.5) (8.314)
= 12.5
Q denotes the Amount of heat absorbed i.e 100 J
We know that
Amount of heat absorbed is provided as
Q = n c (T - T_0)
100 = (1) (12.5) (T - 74)
T = 82 K
