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Shalnov [3]
3 years ago
10

What is a 5% increase of 79

Mathematics
1 answer:
Andreas93 [3]3 years ago
6 0
82.95. because (79x5)/100 = 3.95
3.95 + 79 = 82.95

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A circle has a radius of 11 in. Find the length s of the arc intercepted by a central angle of 11°.
Travka [436]

Answer:

Step-by-step explanation:

11 degrees to radians: 1 degree =57.296 radians

L = (11 degrees)/(57.296) x (11 in) = 2.111848 in

7 0
3 years ago
I need these 2 questions answered please.​
Sav [38]

The area of the circle is 28 ft square.

The area of the triangle is 30 ft square.

Step-by-step explanation:

1) The area of the circle= π*r^2

where π= 3.14(default value) and "r" is the radius of the circle.

Here, Radius of the circle(r)= 3 ft

Area = 3.14*3*3

        = 28.26 ft sq.= 28 ft sq(rounded to the nearest whole number)

2) The triangle has the base= 10 feet and height= 6 feet

The Area of the triangle= 1/2(b)(h)

where "b" is the base and "h" is the height of the triangle.

Substitute b=10 and h=6 ,

Area of triangle= 1/2(10 ft)(6 ft)= 60/2= 30 feet sq.

5 0
3 years ago
Two possible solutions of are -7 and 1. Which statement is true?
quester [9]

We can plug those values into the equation, and if the answer is incorrect, we'll know if either one is extraneous.

√11 - 2(-7) = √(-7)^2 + 4(-7) + 4

√25 = √25

5 = 5

The first solution, -7, makes the equation true, and so it is not extraneous.

√11 - 2(1) = √(1)^2 + 4(1) + 4

√9 = √9

3 = 3

The second solution, 1, makes the equation true, and so it is also not extraneous.

<h3>The correct option is D, neither solution is extraneous. </h3>
4 0
3 years ago
I’ll give 20 points for the ans and equation.
Hunter-Best [27]

Answer: I believe it would be 1.25, because 1.42 times 55000 is 78100, and 1.25 times 64000 is 80000, and 80000 is greater than 78100.

(not completely sure though, I'm not the brightest)

Step-by-step explanation:

5 0
2 years ago
Suppose you have 48 feet of fencing to enclose a rectangular dog pen. The function
Veseljchak [2.6K]

have you figured out the answer i need help on the problem to

6 0
3 years ago
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