Answer:
Step-by-step explanation:
4/5a*3/2a^2
4*3/5a*2a^2
12/10a^3
6/5a^3
therefore ur answer is 6/5a^3
24)
The number 1/10 can be expressed as a decimal by dividing the top number by the bottom.
1/10=0.1
0.8>0.1
0.8>1/10
26)
The number 3/5 can also be expressed as a decimal, using the method I described for 24.
3/5=0.6
0.6>0.35
3/5>0.35
28)
The number 2/5 can also be expressed as a decimal.
2/5=0.4
0.4>0.3
2/5>0.3
30)
The number 1/6 cannot be expressed as a decimal. So, express 0.2 as a fraction.
0.2=2/10=1/5
1/5=6/30
1/6=5/30
6/30>5/30
0.2>1/6
Hope this helps!
Answer: tea = 15 rupees per kg
sugar= 3 rupees per kg
Step-by-step explanation:
Hi, to answer this question we have to write a system of equations with the information given:
<em>"Two kg of tea and 3 kg of sugar cost rupees 39 in january 1997":
</em>
2 t + 3 s =39 (a)
Where:
- t= price of 1 kg of tea
- s = price of 1 kg of sugar
<em>"in march 1997 the price of the tea increased by 25% (1.25)and the price of the sugar increased by 20%(1.20) and the same quantity of tea and sugar cost rupees 48.30.
"</em>
2(t1.25)+3(s1.2) = 48.30 (b)
- <em>Solving for t in (b)
</em>
2t =39-3s
t = (39 -3s)/2
t = 19.5-1.5s
- <em>Replacing the value of t in (b)
</em>
2 x ((19.5-1.5s)1.25)+ 3 ( 1.2s) =48.30
2x ( 24.375 -1.875s) +3.6s =48.30
48.75 -3.75s+3.6s= 48.30
48.75-48.30 = 3.75s-3.6s
0.45= 0.15s
0.45/0.15 =s
3 =s
- <em>Replacing the value of s in (a)
</em>
2 t + 3 (3) =39
2 t + 9 =39
2 t =39 -9
2 t =30
t = 30/2
t= 15
Prices in january:
tea = 15 rupees per kg
sugar= 3 rupees per kg
Feel free to ask for more if needed or if you did not understand something.
The answer is 4 So yeaaaa....
