They’re called periods, answer A
Answer:
6.22g of CaCl₂
Explanation:
Mass of HCL = 4.09g
Mass of CaCl₂ =
equation of reaction
2HCl + Ca(OH)₂ → CaCl₂ + 2H₂O
From equation of reaction, 2 moles of HCl produces 1 mole of CaCl₂
2(36.5)g of HCl = 111g of CaCl₂
73g of HCl will produce 111g of CaCl₂
4.09g of HCl will produce = x
73g of HCl = 111g of CaCl₂
4.09g of HCl = x
Cross multiply and solve for x
X = (111 * 4.09) / 73
X = 6.219g of CaCl₂ = 6.22g of CaCl₂
4.09g of HCl will produce 6.22g of CaCl₂
Answer:
The answer to your question is 144 kg
Explanation:
Data
Q = 8669 kJ
T1 = 75°F
T2 = 195°F
Cp = 0.897 J/(g°C)
m = ?
Formula
Q = mCp(T2 - T1)
Process
1.- Convert temperature to °C
T1 = (75 - 32) / 1.8
= 43/1.8
= 23.9°C
T2 = (195 - 32) / 1.8
= 163/1.8
= 90.6°C
2.- Solve for m
m = Q / Cp(T2 - T1)
3.- Substitution
m = 8669000 / 0.897(90.6 - 23.9)
4.- Simplification
m = 8669000 / 59.83
5.- Result
m = 144893.66 g or 144.9 kg
The percent composition of a compound is calculated with the molecular formula: divide the mass of each element found in one mole of the compound by the total molar mass of the compound
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