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eduard
3 years ago
11

Calculate the molarity of a solution consisting of 60.0 g of NaOH in 1.50 L of solution.

Chemistry
1 answer:
Trava [24]3 years ago
7 0

Explanation:

here's the answer to your question

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Here is my question only answer if you understand this question​
sasho [114]
1- false
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5- true
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Hope it helps :)
8 0
3 years ago
What energy is needed to make evaporation happen
Stella [2.4K]
Heat energy is needed for evaporation to happen.
8 0
3 years ago
A compound has a molar mass of 90. grams per mole and the empirical formula CH2O. What is the molecular formula of this compound
k0ka [10]

Answer:

C₃H₆O₃

Explanation:

Data:

EF = CH₂O

MM = 90. g/mol

Calculations:

EF Mass = (12.01 + 2.016  + 16.00) u  = 30.03 u

The molecular formula is an integral multiple of the empirical formula.

MF = (EF)ₙ

n = \dfrac{\text{MF Mass}}{\text{EF Mass }} = \dfrac{\text{90. u}}{\text{30.03 u}} = 3.00  \approx 3

MF = (CH₂O)₃ = C₃H₆O₃

7 0
3 years ago
Balance this equation. If a coefficient of "1" is required, choose "blank" for that box. CO + O2 → CO2
liberstina [14]

Answer:

2co + o2 > 2co2

Explanation:

so that is tye answer

3 0
3 years ago
Read 2 more answers
To understand the relation between the strength of an acid or a base and its pKa and pKb values. The degree to which a weak acid
elena-14-01-66 [18.8K]

Answer:

pKa = 3.675

Explanation:

  • pKa = - Log Ka

∴ <em>C</em> X-281 = 0.079 M

∴ pH = 2.40

let X-281 a weak acid ( HA ):

∴ HA ↔ H+ + A-

⇒ Ka = [H+] * [A-] / [HA]

mass balance:

⇒<em> C</em> HA = 0.079 M = [HA] + [A-]

⇒ [HA] = 0.079 - [A-]

charge balance:

⇒ [H+] = [A-] + [OH-]... [OH-] is negligible; it comes from to water

⇒ [H+] = [A-]

∴ pH = - log [H+] = 2.40

⇒ [H+] = 3.981 E-3 M

replacing in Ka:

⇒ Ka = [H+]² / ( 0.079 - [H+] )

⇒ Ka = ( 3.981 E-3 )² / ( 0.079 - 3.981 E-3 )

⇒ Ka = 2.113 E-4

⇒ pKa = - Log ( 2.113 E-4 )

⇒ pKa = 3.675

8 0
3 years ago
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