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3 years ago

Which would increase the amount of dissolved oxygen in a pond

Chemistry

1 answer:

AlexFokin [52]3 years ago

6 0

Answer:

Dissolved oxygen levels are increased by supplementing wind and wave action, adding plants to water and exposing water to purified oxygen. Also removing fish could increase the amount of dissolved oxygen

Explanation:

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Plz help, I will give brainliest.

baherus [9]

Answer: The value of $K_c$ is 2

Explanation:

Moles of $N_2O_4$ = 1.0 mole

Volume of solution = 1.00 L

Initial concentration of $N_2O_4$ = $\frac{1.0mol}{1.00L}=1.0M$

Equilibrium concentration of $NO_2$ = $\frac{1.0mol}{1.00L}=1.0M$

The given balanced equilibrium reaction is,

$N_2O_4(g)\rightleftharpoons 2NO_2(g)$

Initial conc. 1.0 M 0 M

At eqm. conc. (1.0-x) M (2x) M

The expression for equilibrium constant for this reaction will be,

$K_c=\frac{[NO_2]^2}{[N_2O_4]}$

Given : 2x = 1.0

x= 0.5

Now put all the given values in this expression, we get :

$K_c=\frac{(1.0)^2}{(1.0-0.5)}$

$K_c=2$

Thus the value of $K_c$ is 2

4 0

3 years ago

This type of bond is made possible by the unequal sharing of electrons within a single molecule

Anestetic [448]

Answer:

POLAR COVALENT

Explanation: A polar covalent bond is a covalent bond in which the atoms have an unequal attraction for electrons and so the sharing is unequal. In a polar covalent bond, sometimes simply called a polar bond, the distribution of electrons around the molecule is no longer symmetrical.

8 0

4 years ago

Read 2 more answers

What is the mass, in grams, of a sample of 6.98 × 1024 atoms of magnesium (Mg)? Show your work or explain the steps that you use

CaHeK987 [17]

Hello!

* First Step: to know Avogrado's Law

We know that by the Law of Avogrado, for each mole of substance we have 6.02*10²³ atoms, if:

** Second Step: to know the molar mass of the solute

The molar mass of of magnesium = 24.30 g/mol

*** Third step: make the ratio mass / mol with atoms

1 mol we have 6.02*10²³ atoms

1 mole of Mg we have 24.30 g

Then we have:

24.30 g ------------- 6.02*10²³ atoms

x ----------------------- 6.98*10^24 atoms

$\dfrac{24.30}{x} = \dfrac{6.02*10^{23}}{6.98*10^{24}}$

multiply cross

$6.02*10^{23}*x = 24.30*6.98*10^{24}$

$6.02*10^{23}\:x = 1.69614*10^{26}$

$x = \dfrac{1.69614*10^{26}}{6.02*10^{23}}$

$\boxed{\boxed{x \approx 281.75\:grams}}\end{array}}\qquad\checkmark$

I Hope this helps, greetings ... DexteR! =)

7 0

3 years ago

A 50.0 mL of 0.88 M H2O2 and 10.0 mL of 0.50 M Fe(NO3)3 were combined and a temperature change of 7.47 was observed. The specifi

Shtirlitz [24]

Answer:

The heat of reaction -1.9 kilo Joules.

Explanation:

Volume of the hydrogen peroxide solution = 50.0 mL

Volume of the ferric nitrate solution = 10.0 mL

Total volume of the solution = 50.0 mL + 10.0 mL = 60.0 mL

Mass of the final solution = m

Density of water = density of the final solution = d = 1 g/mL

$Mass=density\times Volume$

$m=1 g/ml\times 60.0 ml=60.0 g$

Heat capacity of the mixture = c = 4.18 J/g°C

Change in temperature of the mixture = ΔT = 7.47°C

Heat absorbed by the mixture = Q

$Q=mc\Delta T$

$Q=60.0 g\times 4.18 J/g ^oC\times 7.47 ^oC=1873.48 J=1.873 kJ\approx 1.9 kJ$

Heat release due to reaction = -Q'

-Q' =Q (law of conservation of enrage)

Q'= -Q = -1.9 kJ

The heat of reaction -1.9 kilo Joules.

7 0

4 years ago

Differentiate between respiration and combustion

xxMikexx [17]

Answer:

Both combustion and respiration involve the burning of the substrate. In both of these processes, the substance undergoes oxidation (in presence of oxygen).

...

Difference Between Respiration and Combustion.

Respiration Combustion

It takes place in a controlled manner inside the cells. It is an uncontrollable process.

Explanation:

7 0

3 years ago