Answer:
The answer to your question is maybe letter D, but the last oxygen needs a number 6.
Explanation:
The empirical formula gives the actual elements that form part of a molecule but not the total numbers.
The molecular formula gives the total number of atoms of each element in a molecule.
We must factor the molecular formula to know if a formula is the empirical formula of that.
A. CH₄ C₂H₆ = 2(CH₃) these are not empirical molecular formulas
B. CH₂O C₄H₆O these are not empirical-molecular formulas
C. O₂ O₃ these are not empirical-molecular formulas
D. C₃H₄O₃ C₆H₈O these are not empirical-molecular formulas
the last oxygen needs a number 6 to be
the answer.
When liquids are subjected to lower temperatures, the kinetic energy of the molecules would decrease accordingly making them closer to each other and leading to a decrease in volume until the substance is solidified. Hope this answers the question.
The brown Haze that forms over Sunny cities like Los Angeles is called smog. It <span> is a yellowish or blackish fog formed mainly by a mixture of pollutants in the atmosphere which consists of fine particles and ground level ozone.</span><span> Hope this answers the question.</span>
Answer:
The answer to your question is m = 4.7 kg
Explanation:
Data
Ice Water
mass = ? mass = 711 g
T₁ = -13°C T₁ = 87°C
T₂ = 10°C T₂ = 10°C
Ch = 2090 J/kg°K Cw = 4180 J/kg°K
Process
1.- Convert temperature to kelvin
T₁ = 273 + (-13) = 260°K
T₁ water = 87 + 273 = 360 °K
T₂ = 10 + 273 = 283°K
2.- Write the equation of interchange of heat
- Heat lost = Heat absorbed
- mwCw(T₂ - T₁) = miCi(T₂ - T₁)
-Substitution
- 0.711(4180)(10 - 87) = m(2090)(10 - (-13))
- Simplification
228842.46 = 48070m
m = 228842.46/48070
-Result
m = 4.7 kg
Answer:
(a) the mass of the water is 3704 g
(b) the mass of the water is 199, 285.7 g
Explanation:
Given;
Quantity of heat, H= 8.37 x 10⁶ J
Part (a) mass of water (as sweat) need to evaporate to cool that person off
Latent heat of vaporization of water, Lvap. = 2.26 x 10⁶ J/kg
H = m x Lvap.
mass in gram ⇒ 3.704 kg x 1000g = 3704 g
Part (b) quantity of water raised from 25.0 °C to 35.0 °C by 8.37 x 10⁶ J
specific heat capacity of water, C, 4200 J/kg.°C
H = mcΔθ
where;
Δθ is the change in temperature = 35 - 25 = 10°C
mass in gram ⇒ 199.2857 kg x 1000 g = 199285.7 g
