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ohaa [14]
3 years ago
8

Which would increase the amount of dissolved oxygen in a pond

Chemistry
1 answer:
AlexFokin [52]3 years ago
6 0

Answer:

Dissolved oxygen levels are increased by supplementing wind and wave action, adding plants to water and exposing water to purified oxygen. Also removing fish could increase the amount of dissolved oxygen

Explanation:

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What is the electron configuration for 1s2 2s2 2p6 3s2 3p6​
Sliva [168]
This is going to lead you to the element Argon. Is this what you are asking?
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He substance, cocl2, is useful as a humidity indicator because it changes from pale blue to pink as it gains water from moist ai
Anettt [7]

Answer:

Cobalt chloride

Explanation:

It is a molecule formed of one Cobalt atom, and two Chlorine atoms.

5 0
3 years ago
4. Energy can be conserved by -
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Energy can be conserved by efficient energy use.

Answer: Option A

<u>Explanation:</u>

Energy can be transferred from one form to another, but it cannot be destroyed or created. So it can be conserved if efficiently used. Thus efficient usage of energy lead to conservation of energy. Due to conservation of energy, the forces can be renewable and non-renewable.

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4 0
3 years ago
Identify three nonmetal atoms that, when bonded covalently, have an argon electron configuration.
Advocard [28]

Answer:

Phosphorus

Sulphur

And chlorine are non metals when bonded covalently gain electronic configuration of argon

Like PCl3

SO2 and HCl

Explanation:

8 0
3 years ago
PLEEASE HELP TIMED WILL GIVE BRAINLIEST TO CORRECT ANSWER NLY PLEASEEEE HELPPPP
Arturiano [62]

Answer:

1) 1.15 mol

2) M=0.45

3) 22.5 mL

4) 6.25 mL

Explanation:

1)

550 mL= 0.55 L

M= mol solute/ L solution

mol solute= M * L solution

mol solute= (2.1 M * 0.55 L )        M=1.15 mol solute

2)

155 mL = 0.155 L

80 g  -> 1 mol NH4NO3

5.61 g -> x

x= (5.61 g * 1 mol NH4NO3)/80 g       x= 0.07 mol NH4NO3

M=(0.07 mol NH4NO3)/0.155 L         M=0.45

3) M1V1=M2V2

V1= M2V2/M1

V1= (0.500 M * 0.225 L)/5.00 M             V1=0.0225 L =22.5 mL

4) M1V1=M2V2

V1= M2V2/M1

V1= (0.25 M * 0.45 L)/ 18.0 M

V1=6.25 x 10^-3 L = 6.25 mL

8 0
3 years ago
Read 2 more answers
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