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sukhopar [10]
3 years ago
5

Describe how water may be treated before it is used by people?

Physics
2 answers:
lions [1.4K]3 years ago
6 0
You can heat it to get rid of bacteria.
slamgirl [31]3 years ago
5 0
It can be purified or be used by a filter
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A roller coaster, traveling with an initial speed of 21 m/s, decelerates uniformly at -3.5
liberstina [14]

Answer:

S = Vo t + 1/2 a t^2       distance traveled

t = (V2 - V1) / a = (0 - 21) / -3.5 = 6 sec       time to stop

S = 21 * 6 - 3.5 * 6^2 / 2 = 63 m        distance traveled

3 0
1 year ago
A ball is ejected to the right with an unknown horizontal velocity from the top of a pillar that is 50 meters in height. At the
dimulka [17.4K]

Answer:

15.67 m/s

Explanation:

The ball has a projectile motion, with a horizontal uniform motion with constant speed and a vertical accelerated motion with constant acceleration g=9.8 m/s^2 downward.

Let's consider the vertical motion only first: the vertical distance covered by the ball, which is S=50 m, is given by

S=\frac{1}{2}gt^2

where t is the time of the fall. Substituting S=50 m and re-arranging the equation, we can find t:

t=\sqrt{\frac{2S}{g}}=\sqrt{\frac{2(50 m)}{9.8 m/s^2}}=3.19 s

Now we now that the ball must cover a distance of 50 meters horizontally during this time, in order to fall inside the carriage; therefore, the velocity of the carriage should be:

v=\frac{d}{t}=\frac{50 m}{3.19 s}=15.67 m/s

8 0
3 years ago
A gas is compressed in a cylinder from a volume of 20.0 l to 2.0 l by a constant pressure of 10.0 atm. calculate the amount of w
jok3333 [9.3K]
First, we need to convert the pressure in SI units. Keeping in mind that 1 atm = 1.01 \cdot 10^5 Pa:
p=10.0 atm =1.01 \cdot 10^6 Pa

The initial and final volume of the gas are (keeping in mind that 1.0 L = 0.001 m^3):
V_i = 20.0 L=0.020 m^3
V_f = 2.0 L=0.002 m^3

So, the work done on the gas by the surrounding is
W= -p \Delta V=-p(V_f-V_i)=-(1.01 \cdot 10^6 Pa)(0.002 m^3-0.020 m^3)=18180 J
And the final positive sign means that this work corresponds to an increase in internal energy of the gas.
8 0
2 years ago
what would the net force be on the box in the problems shown below.( both force and direction).​ for all four diagrams. please e
DIA [1.3K]

Answer:
A) object moves 20 N [West] or -20 N [East]
B) object moves 6 N [South] or -6 N [North]
C) object moves 90 N [West] or -90 N [East]
D) object does not move and is at rest*

*Rest means 0


Why:

A)both forces from north and south that are pushing against the object neutralize each other. Assume that north is positive and south is negative: 20 [N] + (-20) [S] = 0
On West and east, you can see that west has a greater force. Assume that west is negative and east is positive: 50 [E] + (-70) [W] = -20 [E]
8 0
2 years ago
3) Principles of rectilinear proportion of light 9​
8_murik_8 [283]

Answer:Principle of rectilinear propagation of light

Explanation:Principle of rectilinear propagation of light

Rectilinear propagation of light refers to the propensity of light to travel along a straight line without any interference in its trajectory. ... It is because light travels along a straight line and leaves only the areas where the object interferes.

7 0
2 years ago
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