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Alinara [238K]
1 year ago
14

A roller coaster, traveling with an initial speed of 21 m/s, decelerates uniformly at -3.5

Physics
1 answer:
liberstina [14]1 year ago
3 0

Answer:

S = Vo t + 1/2 a t^2       distance traveled

t = (V2 - V1) / a = (0 - 21) / -3.5 = 6 sec       time to stop

S = 21 * 6 - 3.5 * 6^2 / 2 = 63 m        distance traveled

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Cindy exerts a force of 40 newtons and moves a chair 6 meters. Her brother Andy pushes a different chair for 6 meters while exer
klasskru [66]
Work formula:
W = F * d
F 1 = 40 N, d 1 = 6 m;
F 2 = 30 N; d 2 = 6 m.
W ( Cindy ) = 40 * 6 = 240 Nm
W ( Andy ) = 30 * 6 = 180 Nm
The difference of their amounts if work:
240 Nm - 180  Nm = 60 nm

hope it helps!
3 0
3 years ago
Check my answer(there’s one above) I really just chose my best guess on this.for the ones below, can you provide a simple explan
almond37 [142]

#1

For closed pipe the fundamental frequency will be given as

f = \frac{v}{4L}

153 = \frac{340}{4L}

L = 0.56 m

L = 55 cm

#2

For open pipe the wavelength for Nth harmonic will be given as

n \times \frac{\lambda}{2} = L

\lambda = \frac{2L}{n}

#3

for a closed pipe the frequency is given as

f = \frac{nv}{4L}

here for third harmonic n = 3

f = \frac{3v}{4L}

now plug in all values

235 = \frac{3\times 340}{4L}

L = 1.09 m

L = 109 cm

#10

since in the given figure there are three complete loops

so in this case the <em>number of harmonics are THREE</em>

3 0
3 years ago
C
maksim [4K]

Answer:

b

Explanation:

a,f,,and g is correct because it is indicated that object moving forward

4 0
2 years ago
4. You are walking at a leisurely pace of .75 m/s when you hear the train coming and start running to catch it. Over the next 10
hjlf

Answer:

0.275 m/s²

Explanation:

The acceleration of an object is defined as the change in velocity over the change in time.

  • a = Δv/Δt
  • a = (v - v₀)/t

We are given the initial velocity, 0.75 m/s. The final velocity of the user in question is 3.5 m/s.

The time it takes for us to catch the train is 10 seconds. Using these variables, let's substitute into our equation.

  • a = (3.5 - 0.75)/10
  • a = 2.75/10
  • a = 0.275 m/s²

Our acceleration over that time was 0.275 m/s² in order to catch the train.

5 0
3 years ago
Tornadoes can reach speeds up to 300 mph. True or false?
zimovet [89]
Tornadoes can reach300mph
5 0
3 years ago
Read 2 more answers
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