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murzikaleks [220]
2 years ago
5

How to increase the current in a circuit

Physics
1 answer:
ivann1987 [24]2 years ago
3 0

Answer:

So to increase current of the circuit what you can do is :

1. Use conductor of low resistivity, ¶.

2. Use conductor of small length.

3. Use thick wire.

4. Decrease the temperature of the circuit.

5. If operating temprature is high than use semiconductor, because it have negative temprature coefficient.

6. Minimise the circuit losses.

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800m/s

Explanation:

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A sound wave with a frequency of 400 Hz is moving through a solid object. If the wavelength of the sound wave is 8 m, what is th
Paraphin [41]

Answer:

v = 3200 m/s

Explanation:

As we know that the frequency of the sound wave is given as

f = 400 Hz

wavelength of the sound wave is given as

\lambda = 8 m

so now we have

speed = wavelength \times frequency

so we will have

v = (8m) \times (400 Hz)

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4 0
3 years ago
A bowling ball is 21.6 cm in diameter. What is the angular speed of these ball whenit is moving at 3.0 m/s?
sergejj [24]

Answer:

Angular speed = 27.78 rad/s (Approx)

Explanation:

Given:

Diameter = 21.6 cm

Speed = 3 m/s

Find:

Angular speed

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Radius = 21.6 / 2 = 10.8 cm = 0.108 m

Angular speed = v / r

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Angular speed = 27.78 rad/s (Approx)

3 0
2 years ago
A student shakes a rope such that 20 complete vibrations are made in 4.00 seconds. Determine the vibrational frequency of the ro
fgiga [73]

Answer:

The vibrational frequency of the rope is 5 Hz.

Explanation:

Given;

number of complete oscillation of the rope, n = 20

time taken to make the oscillations, t = 4.00 s

The vibrational frequency of the rope is calculated as follows;

Frequency = \frac{number \ of \ complete \ vibrations}{time \ taken} \\\\Frequency = \frac{20 }{4 \ s} \\\\Frequency = 5 \ Hz

Therefore, the vibrational frequency of the rope is 5 Hz.

8 0
2 years ago
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