Answer:
The specific heat of iron is 0.45 J/g.°C
Explanation:
The amount of heat absorbed by the metal is given by:
heat = m x Sh x ΔT
From the data, we have:
heat = 180.8 J
mass = m = 22.44 g
ΔT = Final temperature - Initial temperature = 39.0°C - 21.1 °C = 17.9°C
Thus, we calculate the specific heat of iron (Sh) as follows:
Sh = heat/(m x ΔT) = (180.8 J)/(22.44 g x 17.9°C) = 0.45 J/g.°C
Answer:
Aqueous layer (1 M HCI)
Explanation:
First of us I want to remind you of the cliché in chemistry that like dissolves like. In solvent extraction, a mixture is dissolved in a system consisting of two immiscible solvents. One layer is organic while the other layer is aqueous.
Polar substances partition in the aqueous layer while nonpolar substances partition in the organic layer.
Since Copper sulfate is ionic, we will find it in the aqueous layer according to the old chemistry cliche.
Answer:
What do you mean what happened?
Explanation:
???
Answer:
The element with electron configuration 1s² 2s² 2p⁶ will most likely not........
Explanation:
I think the answer is (1) Co. Because the element of Cobalt also has 2 electrons at the outer layer which is the same as Calcium. And the outer layer is an important factor which can affect the property of an element.
