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juin [17]
3 years ago
14

WILL MARK BRAINLIEST

Chemistry
2 answers:
vaieri [72.5K]3 years ago
7 0

Answer:D

Explanation:

gregori [183]3 years ago
3 0

Answer:

D) Group 18

Explanation:

Elements in group 18 doesn't't possess any of the properties above

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Murrr4er [49]

Answer:

its A

Explanation:

becasue when blue litmus paper turns red the substance has a pH level below 7,and when it stays blue it is above 7.

7 0
3 years ago
Sort the metric system prefixes into the correct order, smallest to largest.
AleksAgata [21]

Answer:

mili

hecto

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deca

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Explanation:

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3 years ago
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Match the Parts of a Transverse Wave Question 4 options: Distance from rest position to the crest or trough Lowest point of a wa
Mashcka [7]
Answers to wave questions:
1) trough - lowest point of the wave.
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6 0
4 years ago
Which statement is true of a chemical change?. A.. It involves changes in the molecular structure.. B.. It involves changes in p
drek231 [11]
A is the answer. Chemical changes happen when atomic bonds are broken or created during chemical reactions. Hence, in this case, it involve changes to molecular structure.

- Change in states are physical changes.

- When salts are dissolved in water, you can use Distillation to separate them. Distillation is a physical change as well.

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3 0
3 years ago
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Given that Kp = 3.5 x 10-4 for the reaction 2 CO(g) <=> C(graphite) + CO2(g), what is the partial pressure of CO2(g) at eq
spin [16.1K]

<u>Answer:</u> The partial pressure of carbon dioxide at equilibrium is 0.0056 atm

<u>Explanation:</u>

The given chemical equation follows:

                     2CO(g)\rightleftharpoons C\text{ (graphite)}+CO_2(g)

<u>Initial:</u>             4.00

<u>At eqllm:</u>       4.00-2x        x                 x

The expression of K_p for above reaction follows:

K_p=\frac{p_{CO_2}}{(p_{CO})^2}

The partial pressure of pure solids and liquids are taken as 1 in the equilibrium constant expression.

We are given:

K_p=3.5\times 10^{-4}

Putting values in above expression, we get:

3.5\times 10^{-4}=\frac{x}{(4-2x)^2}\\\\x=0.0056,718.28

Neglecting the value of x = 718.28 because equilibrium pressure cannot be greater than initial pressure

Partial pressure of CO_2 = 0.0056 atm

Hence, the partial pressure of carbon dioxide at equilibrium is 0.0056 atm

4 0
3 years ago
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