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Lostsunrise [7]
2 years ago
6

Marcus read that systems provide feedback, or the return of information. Feedback can either cause a change in the system or kee

p it stable. Melting glaciers are an example of positive feedback. Why is this considered positive feedback?
A. Melting glaciers would add more water to the hydrosphere, making it wetter.
B. Melting glaciers would change the land around it, speeding up erosion.
C. Melting glaciers would let the uncovered air and land warm, which speeds up the melting.
D. Melting glaciers would mean more ice at its top, which would slow the glaciers melting.

Chemistry
1 answer:
Rashid [163]2 years ago
8 0
D. Melting glaciers would mean more ice at its top, witch would slow the glaciers down
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Answer:

1.55

Explanation:

-log(M)=pH

- Hope that helps! Please let me know if you need further explanation.

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How do chemical and nuclear reactions differ in(c) Effect on rate of higher reactant concentration?
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Nuclear reactions involve a change in an atom's nucleus, usually producing a different element. Chemical reactions, on the other hand, involve only a rearrangement of electrons and do not involve changes in the nuclei.

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When heating liquid materials in laboratory glassware, a student should always
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If the mass of an object is 60.0 grams and the density of the object is 15.0 g/mL, what is the volume of the object? The formula
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7 0
2 years ago
Ammonia will decompose into nitrogen and hydrogen at high temperature. An industrial chemist studying this reaction fills a 500.
patriot [66]

Explanation:

Chemical reaction equation for the give decomposition of NH_{3} is as follows:.

          2NH_{3}(g) \rightleftharpoons N_{2}(g) + 3H_{2}(g)

And, initially only NH_{3} is present.

The given data is as follows.

  P_{NH_{3}} = 2.3 atm at equilibrium

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Therefore,

          P_{N_{2}} = \frac{0.69 atm}{3}

                        = 0.23 aatm

So, P_{NH_{3}} = 2.3 - 2(0.23)

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Now, expression for K_{p} will be as follows.

         K_{p} = \frac{(P_{N_{2}})(P^{3}_{H_{2}})}{(P^{2}_{NH_{3}})}

           K_{p} = \frac{(0.23) \times (0.69)^{3}}{(1.84)^{2}}

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                     = 0.0224

or,           K_{p} = 2.2 \times 10^{-2}

Thus, we can conclude that  the pressure equilibrium constant for the decomposition of ammonia at the final temperature of the mixture is 2.2 \times 10^{-2}.

6 0
3 years ago
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