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3 years ago

Stock naming please help

Chemistry

1 answer:

andre [41]3 years ago

8 0

Answer:

Can you tell me the question in the comments on this answer or like how you do it then ill answer you in the comments under this answer

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Which of the following locations would experience the highest rate of sublimation?

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I think its the arctic ice caps

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3 years ago

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A chemistry instructor provides each student with 8 test tubes at the beginning of the year. If there are 28 students per class,

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4 years ago

Which statements are inconsistent with dalton's atomic theory as it was originally stated?

Blababa [14]

Missing question:

A. All carbon atoms are identical.

B. An oxygen atom combines with 1.5 hydrogen atoms to form a water molecule.

C. Two oxygen atoms combine with a carbon atom to form a carbon dioxide molecule.

D. The formation of a compound often involves the destruction of one or more atoms.

Answer is: B and D.

A is correct because Daltan stated: All atoms of a given element have the same mass and other properties that distinguish them from the atoms of other elements.

C is correct because atoms combine in simple, whole- number ratios to form compounds, B is incorrect because ratio is not simple, whole number.

D is incorrect because according to Dalton. atoms can't be created or destroyed.

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4 years ago

Science question down below

slavikrds [6]

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3 years ago

Bromine (63 g) and fluorine (60 g) are mixed to give bromine trifluoride. a) Write a balanced chemical reaction. b) What is the

fiasKO [112]

Answer:

a) Br2 + 3F2 → 2BrF3

b) Br2 is the limiting reactant.

c) There will be formed 86.3 grams of BrF3

d) There will remain 0.326 moles of F2 = 12.97 grams

Explanation:

Step 1: The balanced equation

Br2 + 3F2 → 2BrF3

Step 2: Given data

Mass of Bromine = 63grams

Mass of fluorine = 60 grams

percent yield = 80%

Molar mass of bromine = 79.9 g/mol =

Molar mass of fluorine = 19 g/mol

Molar mass of bromine trifluoride = 136.9 g/mol

Step 3: Calculating moles

Moles Br2 = 63 grams / (2*79.9)

Moles Br2 = 0.394 moles

Moles F2 = 60 grams / (2*19.9)

Moles F2 = 1.508

For 1 mole Br2 consumed, we need 3 moles of F2 to produce 2 moles of BrF3

Br2 is the limiting reactant. It will completely be consumed (0394 moles).

There will react 3*0.394 = 1.182 moles of F2

There will remain 1.508 - 1.182 = 0.326 moles of F2 = 12.97 grams

Step 5: Calculate moles of BrF3

For 1 mole Br2 consumed, we need 3 moles of F2 to produce 2 moles of BrF3

So there is 2*0.394 moles = 0.788 moles of BrF3 moles produced

Step 6: Calculate mass of BrF3

mass = Moles * Molar mass

mass of BrF3 = 0.788 moles * 136.9 g/mol = 107.88 grams = Theoretical yield

Step 7: Calculate actual yield

% yield = 0.80 = actual yield / theoretical yield

actual yield = 0.80 * 107.88 grams = 86.3 grams

actual yield = 86.3 grams

7 0

3 years ago