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ElenaW [278]
3 years ago
7

When you balance a chemical reaction, you are making sure that the law of conservation of matter is obeyed?

Chemistry
2 answers:
Alisiya [41]3 years ago
8 0

Explanation:

A balanced chemical reaction is a reaction in which there is equal number of atoms on both reactant and product side. Also, the mass of atoms or compounds present on reactant side equals the mass of atoms or compounds present on product side.

For example, CaSO_{4} + 2HCl \rightarrow CaCl_{2} + H_{2}SO_{4}

Molar mass of CaSO_{4} = 136.14 g/mol

Molar mass of 2HCl = 2 \times 36.46 g/mol = 72.92 g/mol

Therefore, sum of molar mass of reactants = (136.14 + 72.92) g/mol

                                                                       = 209.05 g/mol

Molar mass of CaCl_{2} = 110.98 g/mol

Molar mass of H_{2}SO_{4} = 98.07 g/mol

Therefore, sum of molar mass of products = (110.98 + 98.07) g/mol

                                                                       = 209.05

Therefore, we can see that it is true that when you balance a chemical reaction, you are making sure that the law of conservation of matter is obeyed.

Kitty [74]3 years ago
6 0
<span>Answer: yes, when you balance a chemical reaction, you are making sure that the law of conservation of matter is obeyed.
</span>
<span /><span /><span>
Justification:
</span><span />

<span>1) When you balance a chemical reaction, you add the coefficients to make the number of atoms of each element in the left side of the equation (reactants) equal to number of atoms of the same elements in the right side (products).
</span><span />

<span>2) Since, each atom has a unique atomic mass associated, it results, necessarily, that the mass of the atoms of the reactants is equal to the mass of the atoms of the products</span>.
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Answer:

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<em />

To solve this question we need to find the moles of each reactant in order to solve the molar concentration of each reactan and replacing in the Kc expression. For the reaction, the Kc is:

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<em>Because Kc is defined as the ratio between concentrations of products over reactants powered to its reaction coefficient. Pure liquids as water are not taken into account in Kc expression:</em>

<em />

[H₃O⁺] = 0.110g * (1mol /19.01g) = 0.00579moles / 5.6L = 1.03x10⁻³M

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<h3>Kc = 1.09x10⁻⁴</h3>
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