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3 years ago

HELP ASAP GIVING BRAINLIEST!

Chemistry

1 answer:

nirvana33 [79]3 years ago

6 0

Answer: When a pendulum is at the bottom of its swing, it has kinetic energy.

Explanation: At the bottom of a swing, the greatest speed is achieved. Speed/Velocity equals Kinetic Energy, as potential energy is when speed is at its lowest.

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What are the pH of these solutions?

Tju [1.3M]

Answer:

The answer to your question is below

Explanation:

a) HCl 0.01 M

pH = -log [0.01]

pH = - (-2)

pH = 2

b) HCl = 0.001 M

pH = -log[0.001]

pH = -(-3)

pH = 3

c) HCl = 0.00001 M

pH = -log[0.00001]

pH = - (-5)

pH = 5

d) Distilled water

pH = 7.0

e) NaOH = 0.00001 M

pOH = -log [0.00001]

pOH = -(-5)

pH = 14 - 5

pH = 9

f) NaOH = 0.001 M

pOH =- log [0.001]

pOH = 3

pH = 14 - 3

pH = 11

g) NaOH = 0.1 M

pOH = -log[0.1]

pOH = 1

pH = 14 - 1

pH = 13

3 0

3 years ago

When you receive a loan, the money the lender gives you is called the ____________. A. Interest B. Line of credit C. Principal D

Reika [66]

C. Principal !!!!!!!!!

8 0

3 years ago

Read 2 more answers

When electrons are added to the outter most shell of carbon atom it forms

GalinKa [24]

Answer:

An anion that has a larger radius.

Explanation:

3 0

3 years ago

Combustion of hydrocarbons such as undecane (C_11H_24) produces carbon dioxide, a "greenhouse gas." Greenhouse gases in the Eart

bekas [8.4K]

Answer:

Volume of carbon dioxide is 428.23 L.

Explanation:

Below is the chemical reaction or chemical equation for the combustion of hydrocarbons such as undecane into carbon dioxide.

$C_{11}H_{24}(l) + 17O_{2}(g) \to 11CO_{2} (g) + 12H_2O(g)$

Here, undecane is in liquid form that reacts with gaseous oxygen (combustion) and produces carbon dioxide and water as a product in the gaseous form.

The molar mass of undecane = $156.31 g/mol.$

$\text{Number of moles} = \frac{260g}{156.31g/mol} = 1.66 \ mol.$

From the equation, it can be seen that 1 mole of undecane produces 11 moles of carbon dioxide. Therefore, 1.66 mol will produce 18.26 mol of carbon dioxide.

Now find the volume of 18.26 mol of carbon dioxide when the temperature is 13 degrees Celsius and pressure is 1 atm.

$V = \frac{nRT}{P} \\$