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3 years ago

12

What will decrease over time as a result of improved

2 answers:

Semmy [17]3 years ago

5 0

Answer: b

Explanation:

bagirrra123 [75]3 years ago

4 0

Answer:

C

Explanation:

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At what altitude above the earth's surface would the acceleration due to gravity be 4.9 m/s^2? Assume the mean radius of the ear

Mandarinka [93]

We apply the gravity calculation expressed in the formula: g=GM/r2
where G is the gravitational constant, m is the mass and r is the radius
r=√GM/g
(1) Radius = √6.674e-11*5.972e24/8 = 7058 kms Earth radius or surface of earth from center of earth= 6400 kmsSo r= 658 kms from surface of earth.
Gravity 8m/s2 will be at 658 kms from surface of earth.
(2) half gravity= 9.8/2= 4.9 m/s2 Radius=√6.674e-11*5.972e24/4.9 = 9019 kms Half Gravity will exist at 9019-6400= 2619 kms from surface of earth.

4 0

3 years ago

A4.0 kg object is moving with speed 2.0 m/s. A 1.0 kg object is moving with speed 4.0 m/s. Both objects encounter the same const

Evgesh-ka [11]

Answer:

Both objects travel the same distance.

(c) is correct option

Explanation:

Given that,

Mass of first object = 4.0 kg

Speed of first object = 2.0 m/s

Mass of second object = 1.0 kg

Speed of second object = 4.0 m/s

We need to calculate the stopping distance

For first particle

Using equation of motion

$v^2=u^2+2as$

Where, v = final velocity

u = initial velocity

s = distance

Put the value in the equation

$0= u^2-2as_{1}$

$s_{1}=\dfrac{u^2}{2a}$ ....(I)

Using newton law

$a=\dfrac{F}{m}$

Now, put the value of a in equation (I)

$s_{1}=\dfrac{8}{F}$

Now, For second object

Using equation of motion

$v^2=u^2+2as$

Put the value in the equation

$0= u^2-2as_{2}$

$s_{2}=\dfrac{u^2}{2a}$ ....(I)

Using newton law

$F = ma$

$a=\dfrac{F}{m}$

Now, put the value of a in equation (I)

$s_{2}=\dfrac{8}{F}$

Hence, Both objects travel the same distance.

6 0

3 years ago

Suppose two point charges, Q1 and Q2, are separated by a distance d. Which correctly states Coulomb's Law for the electrical for

likoan [24]

The correct answer is (B)

Which is (kQ1Q2) / d^2

7 0

3 years ago

the earth's moon has a gravitational field strength of about 1.6 n/kg near its surface. the moon has a mass of 7.35x10^22 kg. wh

Andrew [12]

Answer:

1750km

Explanation:

8 0

3 years ago

6: A body throws a ball vertically up. It returns to the ground after 5 seconds. Find the velocity with which the ball is thrown

Elodia [21]

Answer:

Explanation:

Ball rises and falls in equal periods. Because it goes by same speeds and same route. Therefore t_{rise} = t_{fall} =2.5 s

In free fall and vertical throw movement: x= (1/2).a.t^{2}

Here, we can find the height of the ball

x= (1/2).5.(2.5^{2}) = 15.625 m

From the attaches V-t graphics, x=V.t/2

15.624=V.(2.5)/2

V=12.5 m/s

3 0

4 years ago