Following your push the ball rolls down the lane at 4.2m/s. What is the net force on the ball as it rolls down the lane at the constant speed?
Acceleration = Change in Velocity / Time Interval
So,
A=15/10
A=1.5m/s.
Acceleration is defined as the rate of change of velocity over time. Acceleration is a vector quantity because it has both magnitude and direction. It is also the second derivative of position with respect to time or the first derivative of velocity with respect to time. Acceleration is the name we give to the process of changing velocity. Because speed is speed and direction.
There are only two ways to accelerate. Either change speed change direction or change both. Acceleration is the rate of change of velocity. At any point in the orbit, the magnitude of the acceleration is given by the rate of change of magnitude and direction of velocity at that point. Velocity is the primary measure of object position and velocity. It can be defined as the distance traveled by an object in a unit of time.
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Answer:
47 ms
well the time it takes to fall 100m is the same time it takes to travel 65m horizontally.
The time to fall vertically, t is sqrt(2d/g). [this comes from d = 1/2at^2]
so t = sqrt(2*100/9.8) = 4.52s.
The vertical speed at that time is g*t = 9.8*4.52 = 44.3m/s
The horizontal speed is the horizontal distance over the same 4.52s, = 65/4.52 = 14.4m/s.
so the final velocity is = sqrt(44.3^2 + 14.4^2) = 47.ms
