F = force applied to hold the weight of the bowling ball = weight of the bowling ball = 75 N
d = distance through which the bowling ball is moved horizontally = 10 meter
θ = angle between the force in vertically upward direction and displacement in horizontal direction = 90
W = work done on the bowling ball
work done on the bowling ball is given as
W = F d Cosθ
inserting the values
W = (75) (10) Cos90
W = (75) (10) (0)
W = 0 J
Answer:
The ball thrown downward
Explanation:
When the ball is thrown vertically, the acceleration of it is the gravity acceleration independent if it is thrown downward or upward. However, the acceleration is a vector, so, when the ball is thrown upward, the movement is against the gravity, so the acceleration is negative, and so, the velocity decreases during time; and when the ball is thrown downward, the movement goes to the gravity, so the acceleration is positive, so the velocity increase after time passes.
A radio frequency identification application would most likely interface with an Operational Data Store.
The Operations Data Store (ODS) is a central database that provides the latest data snapshots from multiple transaction systems for operational reporting.
It allows organizations to combine data in its original format from various sources into a single destination to provide business reporting.
ODS contains integrated updates from operational sources and supports business intelligence (BI) tools to facilitate tactical decision making.
For example, an administrator can configure ODS to pull weekly batches of data from a billing application that is rarely updated, importing individual transaction records as they occur in the sales database(thanks to these database triggers), then combine the two into new relational tables.
As a result, querying and reporting on operational data in ODS comes with the assurance that these integrated tables contain the latest and most relevant snapshots of the business.
Learn more about Operations Data Store here : brainly.com/question/14925154
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Answer:
Stretch in the spring = 0.1643 (Approx)
Explanation:
Given:
Mass of the sled (m) = 9 kg
Acceleration of the sled (a) = 2.10 m/s
²
Spring constant (k) = 115 N/m
Computation:
Tension force in the spring (T) = ma
Tension force in the spring (T) = 9 × 2.10
Tension force in the spring (T) = 18.9 N
Tension force in the spring = Spring constant (k) × Stretch in the spring
18.9 N = 115 N × Stretch in the spring
Stretch in the spring = 18.9 / 115
Stretch in the spring = 0.1643 (Approx)
Answer:
Explanation:
= Charge at 3000 m = 40 C
= Charge at 1000 m = -40 C
= 3000 m
= 1000 m
k = Coulomb constant =
Electric field due to the charge at 3000 m
Electric field due to the charge at 1000 m
Electric field at the aircraft is .