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alisha [4.7K]
3 years ago
6

Holes drilled several kilometers into Earth’s crust provide direct evidence about Earth’s interior in the form of

Physics
2 answers:
aleksandrvk [35]3 years ago
8 0

Answer:

B

Explanation:

They made a hole in the earth, and was only able to scratch the crust but found lots of rocks to help them learn about the earth  

ivanzaharov [21]3 years ago
6 0
C I hope this helps cccccccccccccccccccc
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Below is a circuit schematic of sources and resistors (Figure 3). VS = 10V , R1 = 100Ω, R2 = 50Ω, R3 = 25Ω, IS = 2A. Calculate t
lorasvet [3.4K]

Answer:

V_3\approx 4.28\,\,V

I_1=0.0572\,\,amps

I_3\approx 0.171\,\,amps

Explanation:

Notice that this is a circuit with resistors R1 and R2 in parallel, connected to resistor R3 in series. It is what is called a parallel-series combination.

So we first find the equivalent resistance for the two resistors in parallel:

\frac{1}{Re}= \frac{1}{R1}+\frac{1}{R2}\\\frac{1}{Re}= \frac{1}{100}+\frac{1}{50}\\\frac{1}{Re}= \frac{3}{100}\\Re=\frac{100}{3} \,\,\Omega

By knowing this, we can estimate the total current through the circuit,:

Vs=I\,*\,(\frac{100}{3} +25)\\10=I\,*\,\frac{175}{3} \\I=\frac{30}{175} \,amps

So approximately 0.17  amps

and therefore, we can estimate the voltage drop (V3) in R3 uisng Ohm's law:

V_3=\frac{30}{175} *\,25=\frac{30}{7} \approx 4.28\,\,V

So now we know that the potential drop across the parellel resistors must be:

10 V -  4.28 V = 5.72 V

and with this info, we can calculate the current through R1 using Ohm's Law:

I_1=\frac{V_1}{R_1} =\frac{5.72}{100} =0.0572\,\,amps

4 0
3 years ago
PLEASE ASWR How heavy is the object if it takes 7N to push up a ramp that is 35m long and 9m high?
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Answer:

e

Explanation:

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2 years ago
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diamong [38]
This ain’t the place, bud. If you have a QUESTION, then you can post it here.
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Any five physics problems
kow [346]

Explanation:

There are still some questions beyond the Standard Model of physics, such as the strong CP problem, neutrino mass, matter–antimatter asymmetry, and the nature of dark matter and dark energy.

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3 years ago
If a taxi cab travels 45.8 m/s for 146 s, how far did it travel?<br> Your Answer:
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Answer:

6.68 km

Explanation:

distance = speedxtime

45.8 x 146

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