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luda_lava [24]
3 years ago
14

A 150 cm long string vibrates with 3 loops and its frequency is 80 Hz. What will be the wavelength and velocity of the waves?

Physics
1 answer:
Vlad1618 [11]3 years ago
5 0

Answer:

since each loop is ewuvivalent to one half wave lenght . the length of the string is equal to two halves of a wavelength . put in the form of an equation in the same reasoning also

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If a road does not have a bicycle lane, where must a bicyclist ride their bicycle?
DIA [1.3K]
A bicyclist can ride their bicycle still on the road. Bicycle riders be able to take the public ways which has the similar rights and accountability as motorists and are subject to the same guidelines and protocols. The law says that individuals who ride bikes should ride as nearby to the right side of the road as likely excluding under the following conditions: when passing, preparing for a left go, evading risks, if the lane is too constricted to share, or if oncoming a place where a right turn is approved. In a road which has a bike lane the bicyclists roving slower than road traffic must custom the bike way excluding when creating a left turn, passing, evading hazardous settings, or impending a place where a right turn is approved. 
5 0
3 years ago
A sports car skids off of a wet mountain road at 48.5 m/s and lands in the river, 110
Oxana [17]

Answer:

  about 4.74 seconds

Explanation:

The time to fall distance d from height h is given by ...

  t = √(2d/g)

  t = √(2·110 m/(9.8 m/s^2)) ≈ 4.74 s

It will take the car about 4.74 seconds to fall 110 meters to the river.

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We assume the car's speed is horizontal, so does not add or subtract anything to/from the time to fall from the height.

3 0
3 years ago
A particle with charge − 2.74 × 10 − 6 C −2.74×10−6 C is released at rest in a region of constant, uniform electric field. Assum
s2008m [1.1K]

Answer:

241.7 s

Explanation:

We are given that

Charge of particle=q=-2.74\times 10^{-6} C

Kinetic energy of particle=K_E=6.65\times 10^{-10} J

Initial time=t_1=6.36 s

Final potential difference=V_2=0.351 V

We have to find the time t after that the particle is released and traveled through a potential difference 0.351 V.

We know that

qV=K.E

Using the formula

2.74\times 10^{-6}V_1=6.65\times 10^{-10} J

V_1=\frac{6.65\times 10^{-10}}{2.74\times 10^{-6}}=2.43\times 10^{-4} V

Initial voltage=V_1=2.43\times 10^{-4} V

\frac{\initial\;voltage}{final\;voltage}=(\frac{initial\;time}{final\;time})^2

Using the formula

\frac{V_1}{V_2}=(\frac{6.36}{t})^2

\frac{2.43\times 10^{-4}}{0.351}=\frac{(6.36)^2}{t^2}

t^2=\frac{(6.36)^2\times 0.351}{2.43\times 10^{-4}}

t=\sqrt{\frac{(6.36)^2\times 0.351}{2.43\times 10^{-4}}}

t=241.7 s

Hence, after 241.7 s the particle is released has it traveled through a potential difference of 0.351 V.

6 0
3 years ago
Enter the expression
vlabodo [156]
I see the word "when..." kind of fading out at the end of the first line.
Whatever comes after it may be important.

If you're just supposed to copy the expression into the box,
then the problem is that you left the 'e' out of it.

I'm guessing that you're supposed to enter whatever the expression becomes
when either  N₀ or  ' t ' has some special value that's in the first line.

Just taking a wild guess here . . . . .

If it's  "Enter the expression ..... , when t=0 ." ,
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But that's just a wild guess.  As I pointed out, you cut off
the picture in the middle of the word 'when', and I've got
a hunch that there's something important after it.
6 0
3 years ago
Electric current flows through a long rod generating thermal energy at a uniform volumetric rate of
mario62 [17]
I don't know if you need to complete this question or do it otherwise, however, I managed to find on the Internet on several places this completion of your sentence:
<span>Electric current flows through a long rod generating thermal energy at a uniform volumetric rate of q = 2 x 10</span>⁶ W/m³. 
I'm not sure whether that is the answer you were looking for, but that's what I found.
5 0
3 years ago
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