Question

Three boys and 3 girls are seated randomly in a row. What is the probability that the boys sit together and the girls sit together? 5. (a) 0.10 (b) 0.14 (c) 0.18 (d) 0.22 (e) 0.26

Answer 1

Answer:

The correct answer is 0.1

Step-by-step explanation:

We know the total no of ways in which 3 boys and 3 girls can be seated equals 6!

Now since we want all the 3 girls and the 3 boys to sit together

Let B1 , B2 , B3 be the boys and G1, G2, G3 be the boys and girls respectively

the no of ways to arrange boys = 3!

Similarly the number of ways to arrange girls = 3!

Thus the total no of ways to arrange both boys and girls = 3! x 3!

Thus the probability is given by

$P(E)=\frac{2\times 3!\times 3!}{6!}=\frac{1}{10}=0.1$