Most likely gravity, because the gravity would pull it off course or wobble.
Answer:
10 days
Explanation:
The half-life of a radioactive sample is the time taken for half of the sample to decay.
In the diagram, the half-life corresponds to the time after which the % of cobalt-57 has halved. We can observe the following:
At t=10 days, the % of Co remaining is approximately 45%
At t=20 days, the % of Co remaining is approximately 22%
This means that the sample of cobalt-57 has halved in 10 days, so the half-life of cobalt-57 is 10 days.
Answer:
11. 5 N to the left.
12. 10 N to the right.
Explanation:
11. Determination of the net force.
Force in the left direction (Fₗ) = 10 N
Force in the right direction (Fᵣ) = 5 N
Net force (Fₙ) =?
The net force can be obtained as follow:
Fₙ = Fₗ – Fᵣ (Since the forces act in opposite direction)
Fₙ = 10 – 5
Fₙ = 5 N to left
Thus, the net force is 5 N to the left.
12. Determination of the net force.
Force in the right direction 1 (Fᵣ₁) = 5 N
Force in the right direction 2 (Fᵣ₂) = 5 N
Net force (Fₙ) =?
The net force can be obtained as follow:
Fₙ = Fᵣ₁ + Fᵣ₂ (Since the forces act in the same direction)
Fₙ = 5 + 5
Fₙ = 10 N to the right
Thus, the net force is 10 N to the right.
