Evaluate [7 - (2 - 5(4 - 2) + 7)] + 2

Mathematics

2 answers:

motikmotik3 years ago

7 0

You are correct. here it is step by step.

[7-(2-5(2)+7)] +2
[7-(2-10+7)]+2
[7-(-1)]+2
8+2
10

Roman55 [17]3 years ago

3 0

Order of operations
PEMDAS
parethasees (inner to outer)
exponents
multiplication and division
addition and subtraction
remember thah yuo do all these left to right

so

[7-(2-5(4-2)+7)]+2
inner to outer
4-2=2

now we have
[7-(2-5(2)+7)]+2
multiply since no further parnthasees
2*5=10

now we have
[7-(2-10+7)]+2
add or subtract (subtraction is addition of a negative)
2-10=-8, and -8+7=-1

now we have
[7-(-1)]+2
last parenthsees/brackets
remember that subtracting a negative is the same as adding a positive
7-(-1)=7+1=8

now we have
[8]+2
add
10

yep, 10 is right

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$\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\\\
% left side templates
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f(x)=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
y=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
f(x)=&{{ A}}\sqrt{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}}(\mathbb{R})^{{{ B}}x+{{ C}}}+{{ D}}
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f(x)=&{{ A}} sin\left({{ B }}x+{{ C}} \right)+{{ D}}
\end{array}\\\\
--------------------\\\\$

$\bf \bullet \textit{ stretches or shrinks horizontally by } {{ A}}\cdot {{ B}}\\\\
\bullet \textit{ flips it upside-down if }{{ A}}\textit{ is negative}\\
\left. \qquad \right. \textit{reflection over the x-axis}
\\\\
\bullet \textit{ flips it sideways if }{{ B}}\textit{ is negative}\\
\left. \qquad \right. \textit{reflection over the y-axis}$

$\bf \bullet \textit{ horizontal shift by }\frac{{{ C}}}{{{ B}}}\\
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