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antoniya [11.8K]
3 years ago
11

Evaluate [7 - (2 - 5(4 - 2) + 7)] + 2

Mathematics
2 answers:
motikmotik3 years ago
7 0
You are correct. here it is step by step.

[7-(2-5(2)+7)] +2
[7-(2-10+7)]+2
[7-(-1)]+2
8+2
10
Roman55 [17]3 years ago
3 0
Order of operations
PEMDAS
parethasees (inner to outer)
exponents
multiplication and division
addition and subtraction
remember thah yuo do all these left to right

so


[7-(2-5(4-2)+7)]+2
inner to outer
4-2=2

now we have
[7-(2-5(2)+7)]+2
multiply since no further parnthasees
2*5=10

now we have
[7-(2-10+7)]+2
add or subtract (subtraction is addition of a negative)
2-10=-8, and -8+7=-1

now we have
[7-(-1)]+2
last parenthsees/brackets
remember that subtracting a negative is the same as adding a positive
7-(-1)=7+1=8

now we have
[8]+2
add
10


yep, 10 is right
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3 years ago
What is Permutations and Combinations?
marissa [1.9K]

Answer:

See below

Step-by-step explanation:

Permutation is to select an object then arrange it and it cares about the orders while Combination is about only selecting an object without caring the orders.

Permutation can be expressed in math as:

\displaystyle{_n P _r = \dfrac{n!}{(n-r)!} \ \ \ (n \geq r) }

where n is a number of total object and r is a number of selected object to arrange. Hence. n cannot be less than r.

Now let's see an example of permutation, suppose we have letter A, B and C. I'd like to know how many ways these words can be arranged:

Since there are 3 letters total and 3 selected letters to arrange then:

\displaystyle{_3 P _3 = \dfrac{3!}{(3-3)!}}\\\\\displaystyle{_3 P _3 = \dfrac{3 \times 2 \times 1}{0!}}\\\\\displaystyle{_3 P _3 = \dfrac{6}{1}}\\\\\displaystyle{_3 P _3 = 6}

Therefore, there are 6 ways to arrange the letters - we can also demonstrate visually:

ABC - 1

ACB - 2

BAC - 3

BCA - 4

CAB - 5

CBA - 6

Notice that if you do visually, you'll get the same answer as the calculation of permutation!

----

Combination can be expressed mathematically as:

\displaystyle{_n C _r = \dfrac{n!}{(n-r)!r!} = \dfrac{_n P _r}{r!} \ \ \ (n \geq r) }

The difference between permutation and combination is that you only find how many ways you can select object in combination. Therefore, no arrange and doesn't care about order, just ways to select.

Suppose we have same 3 letters: A, B and C. I want to find how many ways I can select these 3 letters:

Since there are 3 letters total and 3 selected letters:

\displaystyle{_3 C _3 = \dfrac{3!}{(3-3)!3!}}\\\\\displaystyle{_3 C _3 = \dfrac{3!}{0!3!}}\\\\\displaystyle{_3 C _3 = \dfrac{3!}{3!}}\\\\\displaystyle{_3 C _3 = 1}

Hence, there is only one way to select 3 letters. This makes sense because if you have 3 letters then you can only select 3 letters only one way.

5 0
2 years ago
Solve c= 8a-3b for a
Vesnalui [34]

Answer:

(c+3b)/8 = a

Step-by-step explanation:

c= 8a-3b

Add 3b to each side

c+3b= 8a-3b+3b

c+3b = 8a

Divide each side by 8

(c+3b)/8 = 8a/8

(c+3b)/8 = a

6 0
3 years ago
Find the value: 3/2 ÷ 5/8 (write your answer as a fraction AND as a decimal number)
Vikki [24]

Answer:

Decimal : 2.4

Fraction: 2 4/10 or 2 2/5

Step-by-step explanation:

hope this helps :) plz mark brainliest to help my rank

4 0
3 years ago
Read 2 more answers
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